All categories

2 years ago

Li2SO4 _____ an electrolyte in solution. A. Is B. Is not

Chemistry

2 answers:

Rasek [7]2 years ago

8 0

Answer:

Explanation:

it is an electrolyte because of its strong polar chemical bond

yulyashka [42]2 years ago

6 0

It is an electrolyte because it is ionic!

You might be interested in

Un recipiente cerrado, de 4,25 L, con tapa móvil, contiene H2S(g) a 740 Torr y 50,0°C. Se introduce en ese recipiente N2(g) a te

notsponge [240]

Answer:

high schools community of college students who is looking my friend you my friend and maddie intro high college football of community College program maddie I work peen and caty high schools community College program g2

4 0

3 years ago

Calculate the number of moles in 456 grams of lead, Pb

Kamila [148]

Mass 456
relative mass 82
moles
mass = rm x moles
456/82 = 5.5609756....

8 0

3 years ago

Given 700 ml of oxygen at 7 ºC and 106.6 kPa pressure, what volume does it take at 27ºC and 66.6 kPa pressure

o-na [289]

Answer:

The volume is 1.2L

Explanation:

Initial volume (V1) = 700mL = 0.7L

Initial temperature (T1) = 7°C = (7 + 273.15)K = 280.15K

Initial pressure = 106.6kPa = 106600Pa

Final temperature (T2) = 27°C = (27 + 273.15)K = 300.15K

Final pressure (P2) = 66.6kPa = 66600Pa

Final volume (V2) = ?

To solve this question, we need to use combined gas equation which is a combination of Boyle's law, Charles Law and pressure law.

(P1 × V1) / T1 = (P2 × V2) / T2

solve for V2 by making it the subject of formula,

P1 × V1 × T2 = P2 × V2 × T1

V2 = (P1 × V1 × T2) / (P2 × T1)

V2 = (106600 × 0.7 × 300.15) / (66600 × 280.15)

V2 = 22397193 / 18657990

V2 = 1.2L

The final volume of the gas is 1.2L

6 0

3 years ago

NEED HELP ASAP PLEASE

frutty [35]

C. NO2 is covalent. Hope this helps!

6 0

3 years ago

Read 2 more answers

Write balanced, net ionic equations for the following precipitation, acidn base, or gasn forming reactions. Include states of ma

dybincka [34]

Answer:

Explanation:

a ) 2FeCl₃ + 3Li₂S = Fe₂S₃ ( s ) + 6 LiCl

2Fe⁺³ + 6Li ⁻ + 6Cl⁻ + 3S⁻² = 6Li + 6Cl⁻ + Fe₂S₃ ( s )

b )

3CH₃COONa +( NH₄)₃PO₄ = 3CH₃COONH₄ + Na₃PO₄

3CH₃COO + 3Na⁺ + 3NH₄⁻ + PO₄⁺³ = 3CH₃COO⁻ +3NH₄⁺ + Na₃PO₄

c )

HClO₄ + KOH = kClO₄ + H₂O

H ⁺ + ClO₄⁻ + K⁺ + OH⁻ = k⁺ ClO₄⁻ + H₂O

d )

NH₄OH + HNO₃ = NH₄NO₃ + H₂O

NH₄⁺ + OH⁻ + H⁺ + NO₃⁻ = NH₄⁺ + NO₃⁻ + H₂O

e )

HNO₂ + KOH = KNO₂ + H₂O

H⁺ + NO₂⁻ + K⁺ + OH⁻ = K⁺ + NO₂⁻ + H₂O

f ) HIO₃ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃

H⁺ + IO₃⁻ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃

g )

c ) is strong acid and strong base

d ) is weak base and strong acid

e ) weak acid and strong base

f ) Strong acid and basic salt

5 0

2 years ago