Derek walks along a road which can be modeled by the equation y =2x, where (0,0) represents his starting point. When he reaches
the point (7, 14), he turns right, so that he is traveling perpendicular to the original road, until he stops at a point which is due east of his starting point (in other words, on the x-axis). What is the point where Derek stops? Select the correct answer below: (39,0) (38, 0) (31,0) (29, 0) (35, 0) (30,0)
1 answer:
Answer:
(35,0)
Step-by-step explanation:
Consider the diagram below, the starting point is given as A and the finish point given as C.
Using similar right-angle triangle, we have that:
Therefore to find the point where Derek stops at C, we first determine the distance |AC|
|AC|=7+28=35
The Coordinates at C where Derek stops is (35,0)
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Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
