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Masja [62]
3 years ago
11

Rewrite 5V4•V2 as a single radical.

Mathematics
1 answer:
MrRissso [65]3 years ago
6 0

Answer:

5v6 is the answer

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Transforma in metri:
s2008m [1.1K]

Answer:

a) 70 m

b) 35 m

c) 57 m

d) 500 m

e) 7.5 m

f) 57 m

Step-by-step explanation:

10 dm = 100 cm = 1 m.

1 dam = 10 m

1 km = 1000 m

100 cm = m

Correct ☑ ✔ Question :-

Transform in metre

a) 7 dam

b) 350 dm

c) 57000 mm

d) 0.5 km

e) 750 cm

f) 5.7 dam

<h3>Solution ✔</h3>

a) 7 dam

1 dam = 10 m

so, 7 dam = 7 × 10 m = 70 m

b) 350 dm

10 dm = 1 m

so, 350 dm = 350/10 = 35 m

c) 57000 mm

1000 mm = 1 m

so, 57000mm = 57000/1000 = 57 m

d) 0.5 km

1 km = 1000 m

0.5 km = 1000 × 0.5 = 500 m

e) 750 cm

100 cm = 1 m

750 cm = 750/ 100 = 7.5 m

f) 5.7 dam

1 dam = 10 .

5.7 dam = 5.7 × 10 = 57 m

7 0
3 years ago
When decreases in one variable are accompanied by decreases in another variable, the variables are described as?
Oksi-84 [34.3K]
Directly proportional or positively correlated
7 0
3 years ago
Action hero mambo ('the moose with no mercy') has just finished for film for his latest movie. Due to his unique acting style he
solmaris [256]
A. £549 376 / 4 = £137344 per word
B. £549 376 / 16 = £34336 per letter
C. £549 376 / 37 = £14848 per letter
D. £549 376 / 512 = £ 1073
7 0
3 years ago
Maya has 5/6 cup of ice cream. How many 1/4-cup servings are in 5/6 cup of ice cream?
Alla [95]

Answer:

3 and 1 over 3.

Step-by-step explanation:

We divide 5/6  by 1/4.

5 /6 / 1/4

= 5/6 * 4

= 20/6

= 3  2/6

= 3 1/3.

8 0
3 years ago
Read 2 more answers
For the graph, what is a reasonable constraint so that the function is at least 300?
blsea [12.9K]

Answer:

C) 0 ≤ x ≤ 25

Step-by-step explanation:

We are supposed to find a reasonable constraint so that the function is at least 300 i.e. the value of x at which f(x) is greater or equal to 300

A)x ≥ 0

Refer the graph

At x = 0

f(x)=300

On increasing the value of x , f(x) increases but at x = 12 it starts decreasing

So, x ≥ 0 can also have f(x)<300

So, Option A is wrong

B)−5 ≤ x ≤ 30

At x = -5

f(x) = 100

So, Option B is wrong since we require f(x) is greater or equal to 300

c)0 ≤ x ≤ 25

At x = 0

f(x)=300

At x = 12 , it starts decreasing

At x = 25

f(x)=300

So, The value of f(x) is at least 300 when 0 ≤ x ≤ 25

D)All real numbers

At x = 30

f(x)=0

But we require f(x) greater or equal to 300

Hence Option C is true

8 0
3 years ago
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