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julsineya [31]
2 years ago
10

What is the domain and range of the following graph?

Mathematics
2 answers:
lys-0071 [83]2 years ago
7 0
Area is all x - values and reach is all y - values. See the entirety of the x qualities and y esteems that are contacting the diagram. Likewise, when there is a circle use enclosure for the stretch documentation
raketka [301]2 years ago
6 0

Answer:

Domain is all x-values and range is all y values. See all of the x values and y values that are touching the graph. Also, when there is a circle/ hole, use parenthesis for the interval notation.  Hope it helps!

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1/4 divided by 2/3 show work pls
NARA [144]
\dfrac{1}{4}:\dfrac{2}{3}=\dfrac{1}{4}\cdot\dfrac{3}{2}=\dfrac{1\cdot3}{4\cdot2}=\boxed{\frac{3}{8}}
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Graph: y &lt;<br> +<br> y<br> -2<br> 2<br> -2<br> Draw<br> Click or tap the graph to plot a point.
ICE Princess25 [194]

Answer:

I dunno what you wrote at the top, but I solved the picture

Step-by-step explanation:

4 0
3 years ago
Put these numbers in order from greatest to least.<br> 1 6/8,-10/25,-18/25,1
goldenfox [79]

\textsf{Hey there!}

\textsf{Put these numbers in order from GREATEST to LEAST}

\bullet{\mathsf{ \ 1\dfrac{6}{8}}}

\bullet\mathsf{\ -\dfrac{10}{25}}

\bullet{\mathsf{\ -\dfrac{18}{25}}}

\bullet{\textsf{ 1}}

\star\textsf{ We know that fractions, decimals, negatives are BELOW 0 (on the left} \textsf{of 0)}

\star\textsf{ \& we also know that positives and real numbers is/are ABOVE 0 (to the right} \textsf{of 0)}

\textsf{Now we can answer your question}

\blacksquare \ \mathsf{1\dfrac{6}{8} = \dfrac{14}{8} = 1.75}

\blacksquare\ \mathsf{-\dfrac{10}{25} = -0.40}

\blacksquare\ \mathsf{- \dfrac{18}{25} = -0.72}

\blacksquare \ \mathsf{1 = 1}

\textsf{Look carefully at the stuff converted to the decimal or regular number \& } \textsf{you will  have your answer from \underline{greatest} to \underline{least}}

\boxed{\textsf{If you solved correctly you  SHOULD have: \boxed{\mathsf{\dfrac{14}{8}, \ 1, \ - \dfrac{10}{25}\ ,\  -\dfrac{18}{25}}}}}\checkmark

\textsf{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

5 0
4 years ago
PLEASE ANSWER CORRECTLY, I WILL GIVE BRAINLIEST &lt;3 THANKS IN ADVANCE!
guajiro [1.7K]

Answer:

1 : 15

2: 12

3: 52

4: 27.3

Step-by-step explanation:

For #1:

if line m and n are perpendicular then they will create right angles

Right angles have a measure of 90 degrees

That being said we can find the measure of the missing angle by subtracting the measure of the known angle (75) from 90

so k = 90 - 75

90 - 75 = 15

Hence k = 15.

For #3 ( very similar to #1, only difference is the values of the angles )

so R = 90 - 38

90 - 38 = 52

Hence, R = 52

For #2 and #4

Complementary angles have a sum of 90°

So like the previous questions we can find the measure of the missing angle by subtract the measure of the given angle from 90

∠V = 90 - 78

90 - 78 = 12

Hence ∠V = 12

∠Y = 90 - 62.7

90 - 62.7 = 27.3

Hence ∠Y = 27.3

6 0
3 years ago
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