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3 years ago

Help please thank you so much

Mathematics

1 answer:

aleksandr82 [10.1K]3 years ago

8 0

Answer:

it is a function because it doesn't have two x coordinates at the same y coordinate.

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Convert 11/3 from an improper fraction into a mixed number

Sholpan [36]

Answer: 3 2/3

Step-by-step explanation:

how many groups of 3 can u make out of 11 units? Answer: 3

Rest overs: 2/3

5 0

3 years ago

Read 2 more answers

A car advertisement states that a certain car can accelerate from rest to 70 km/h in 7 seconds. Find the cars average accelerati

Ray Of Light [21]

Answer:

v_0(initial velocity) v_f(final velocity) a(acceleration)

v_0=70 km/h v_f= 0 km/h( rest)

Kinematics equation is a=(v_f-v-0)/time

a=(0-70)/(7/3600) which means it decelerates at -36000 km/h

This number is humongous; I would advise you to re-check the problem and see if the the time it takes is 7 hours rather than 7 seconds. Notice that I put the time as 7/3600 because it is 7 seconds which should be converted to hours.

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3 years ago

Y=3x-4 into standard form

tamaranim1 [39]

X = y+4/3

I mean, I hope this helped.

6 0

3 years ago

More Information From the Online Dating Survey A survey conducted in July 2015 asked a random sample of American adults whether

svet-max [94.6K]

Answer:

90% confidence interval for the proportion of all US adults ages 55 to 64 to use online dating is [0.095 , 0.148].

Step-by-step explanation:

We are given that a survey conducted in July 2015 asked a random sample of American adults whether they had ever used online dating.

The survey included 411 adults between the ages of 55 and 64, and 50 of them said that they had used online dating.

Firstly, the pivotal quantity for 90% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of adults who said that they had used online dating = $\frac{50}{411}$ = 0.122

n = sample of adults between the ages of 55 and 64 = 411

p = population proportion of all US adults ages 55 to 64 to use online dating

Here for constructing 90% confidence interval we have used One-sample z proportion statistics.

So, 90% confidence interval for the population proportion, p is ;

P(-1.645 < N(0,1) < 1.645) = 0.90 {As the critical value of z at 5% level

of significance are -1.645 & 1.645}

P(-1.645 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.645) = 0.90

P( $-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.90

P( $\hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.90

90% confidence interval for p = [ $\hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.122-1.645 \times {\sqrt{\frac{0.122(1-0.122)}{411} } }$ , $0.122+1.645 \times {\sqrt{\frac{0.122(1-0.122)}{411} } }$ ]

= [0.095 , 0.148]

Therefore, 90% confidence interval for the proportion of all US adults ages 55 to 64 to use online dating is [0.095 , 0.148].

7 0

3 years ago

This is question please hlep me

Llana [10]

I think the answer is a btw hoped it helped

7 0

3 years ago

Help please thank you so much​

Help please thank you so much