Answer:
A) 1/(3x+1)
Step-by-step explanation:
(x+2)/(x³+2x²-9x-18)÷(3x+1)/(x²-9)
(x+2)/(x+2)(x+3)(x-3)÷(3x+1)/(x+3)(x-3)
since it’s dividing by a fraction, invert and multiply
(x+2)/(x+2)(x+3)(x-3) times (x+3)(x-3)/(3x+1)
The (x+2)’s cancel out.
The (x+3)’s cancel out.
The (x-3)’s cancel out.
You are left with 1/(3x+1)
We can plug those values into the equation, and if the answer is incorrect, we'll know if either one is extraneous.
√11 - 2(-7) = √(-7)^2 + 4(-7) + 4
√25 = √25
5 = 5
The first solution, -7, makes the equation true, and so it is not extraneous.
√11 - 2(1) = √(1)^2 + 4(1) + 4
√9 = √9
3 = 3
The second solution, 1, makes the equation true, and so it is also not extraneous.
<h3>The correct option is D, neither solution is extraneous. </h3>
Answer:
The point (-5, 6) is located in the second quadrant
Step-by-step explanation:
Answer:
1
Step-by-step explanation: