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iVinArrow [24]
3 years ago
8

What is the volume of the following rectangular prism? 3/20 units^2 2/3 units

Mathematics
2 answers:
Blizzard [7]3 years ago
8 0

Step-by-step explanation:

\-x+sqrt1−x

2

\-=sqrt2(2x

2

−1).

\-x+sqrt1−x

2

\-=sqrt2(2x

2

−1).

User avatar

MM

Posts: 82

Joined: Tue Jul 22, 2008 7:36 am

Location: Bulgaria

Reputation: 7

\-x+sqrt1−x

2

\-=sqrt2(2x

2

−1).

User avatar

MM

Posts: 82

Joined: Tue Jul 22, 2008 7:36 am

Location: Bulgaria

Reputation: 7

\-x+sqrt1−x

2

\-=sqrt2(2x

2

−1).

User avatar

MM

Posts: 82

Joined: Tue Jul 22, 2008 7:36 am

Location: Bulgaria

Reputation: 7

\-x+sqrt1−x

2

\-=sqrt2(2x

2

−1).

User avatar

MM

Posts: 82

Joined: Tue Jul 22, 2008 7:36 am

Location: Bulgaria

Reputation: 7

\-x+sqrt1−x

2

\-=sqrt2(2x

2

−1).

User avatar

MM

Posts: 82

Joined: Tue Jul 22, 2008 7:36 am

Location: Bulgaria

Reputation: 7

\-x+sqrt1−x

2

\-=sqrt2(2x

2

−1).

User avatar

MM

Posts: 82

Joined: Tue Jul 22, 2008 7:36 am

Location: Bulgaria

Reputation: 7

\-x+sqrt1−x

2

\-=sqrt2(2x

2

−1).

User avatar

MM

Posts: 82

Joined: Tue Jul 22, 2008 7:36 am

Location: Bulgaria

Reputation: 7

\-x+sqrt1−x

2

\-=sqrt2(2

vladimir1956 [14]3 years ago
6 0

Answer:1/10^3

Step-by-step explanation:

3/20×2/3=1/10^3

Area of the base×height

Hope it helps❤

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Find the solution to the following system of equations: <br><br>y+2x=3<br>y-4x=10​
Korolek [52]

Answer:

x=-7/6, y=16/3. (-7/6, 16/3).

Step-by-step explanation:

y+2x=3

y-4x=10

-----------

y=4x+10

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6x+10=3

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6x=-7

x=-7/6

y+2(-7/6)=3

y-14/6=3

y=3+14/6

y=18/6+14/6

y=32/6=16/3

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4 years ago
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frutty [35]

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Step-by-step explanation:

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4 years ago
Paige was playing a trivia game where you gained points for correct answers and lost points for incorrect answers. At the start
victus00 [196]

Givens

Start = S = - 700

# Correct = C = 8

Value Correct = VC = 400

# Incorrect =I = 9

Value Incorrect =VI =  - 600

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5 0
3 years ago
Adi drew a circle with a radius of 10 cm. What is the area of the circle? Use 3. 14 for pi
tatyana61 [14]

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314

Step-by-step explanation:

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4 0
3 years ago
Evaluate the integral using the indicated trigonometric substitution. (use c for the constant of integration.) x^3 / sqrt x^2 +
slava [35]
\displaystyle\int\frac{x^3}{\sqrt{x^2+49}}\,\mathrm dx

Taking x=7\tan\theta gives \mathrm dx=7\sec^2\theta\,\mathrm d\theta, so that the integral becomes

\displaystyle\int\frac{(7\tan\theta)^3}{\sqrt{(7\tan\theta)^2+49}}(7\sec^2\theta)\,\mathrm d\theta
=\displaystyle7^4\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{49\tan^2\theta+49}}\,\mathrm d\theta
=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\tan^2\theta+1}}\,\mathrm d\theta
=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\sec^2\theta}}\,\mathrm d\theta
=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{|\sec\theta|}\,\mathrm d\theta

When \sec\theta>0, we have

=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sec\theta}\,\mathrm d\theta
=\displaystyle7^3\int\tan^3\theta\sec^2\theta\,\mathrm d\theta

and from here we can substitute u=\tan\theta to proceed from here.

Quick note: When we set x=7\tan\theta, we are implicitly enforcing -\dfrac\pi2 just so that the substitution can be undone later via \theta=\tan^{-1}\dfrac x7. But note that over this domain, we automatically guarantee that \sec\theta>0, so the absolute value bars can be dropped immediately.
6 0
3 years ago
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