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hichkok12 [17]
3 years ago
11

Question 2 options:

Mathematics
1 answer:
Alex777 [14]3 years ago
3 0
7736.4uhshshszszehzeehe
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The sum of the interior angles of Michael’s polygon equals 180°. The sum of the interior angles of Cary’s polygon equals 360°. H
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Recall that for a polygon to have 180° as the sum of its interior angles, then it must have three sides and thus a triangle. And similarly, for a polygon to have a sum of 360°, it must have four sides or it is a quadrilateral.

[Note that for larger angles, we can apply the formula 180(n - 2) to find the total sum of the interior angles. n is the number of sides]

Now, since we're comparing a four-sided and three-sided polygon, this means that they only differ by 1 side. 

Answer: A. 1 side
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Clint is in study hall reading a book. after 20 mins, he is on page 151. after 45 mins, he is on page 181. how many pages has cl
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the answer is: 30 pages

Step-by-step explanation:

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Answer:

The answer to your question is below

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See the picture below

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The figure shows a square and 4 congruent isosceles triangles. If the length of leg x is 12 feet, what is the length in feet of
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Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y
kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

substitute in the formula

d=\sqrt{(5-2)^{2}+(2-0)^{2}}

d=\sqrt{(3)^{2}+(2)^{2}}

dAB=\sqrt{13}\ units

step 2

Find the distance BC

substitute in the formula

d=\sqrt{(7-5)^{2}+(-1-2)^{2}}

d=\sqrt{(2)^{2}+(-3)^{2}}

dBC=\sqrt{13}\ units

step 3

Find the distance AC

substitute in the formula

d=\sqrt{(7-2)^{2}+(-1-0)^{2}}

d=\sqrt{(5)^{2}+(-1)^{2}}

dAC=\sqrt{26}\ units

step 4

Compare the length sides

dAB=\sqrt{13}\ units

dBC=\sqrt{13}\ units

dAC=\sqrt{26}\ units

dAB=dBC

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

(AC)^{2} =(AB)^{2}+(BC)^{2}

substitute

(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}

26=13+13

26=26 -----> is true

therefore

Is an isosceles right triangle

8 0
3 years ago
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