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2 years ago

5

Lara has three cats: Socks, Princess, and Luna. The ratio of Sock's weight to Princess's weight is 4:5. The ratio of Princess's

weight to Luna's weight is 6:7. What is the ratio of Sock's weight to Luna's weight?

2 answers:

romanna [79]2 years ago

6 0

A = Sock's weight
b = Princess' weight
c = Luna's weight

a : b = 4 : 5
b : c = 6 : 7

at this point, we have to change the 2 ratios (a : b and b : c) into one ratio (a : b : c)
to do that, we have to change the ratio number so the number b in both ratio is the same

a : b = 4 : 5 = 24 : 30
b : c = 6 : 7 = 30 : 35
From that we can conclude that
a : b : c = 24 : 30 : 35

Since we're looking for the ratio of Sock's weight to Luna's weight, it will be
a : c = 24 : 35

Kitty [74]2 years ago

6 0

4:7 because 4 is sock's waeight and it says that in the first ratio and 7 is luna's weight because it says that in the last ratio

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Andreas93 [3]

Complete Question

A genetic experiment with peas resulted in one sample of offspring that consisted of 432 green peas and 164 yellow peas. a. Construct a 95% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?

Answer:

The 95% confidence interval is $0.2392 < p < 0.3108$

No, the confidence interval includes 0.25, so the true percentage could easily equal 25%

Step-by-step explanation:

From the question we are told that

The total sample size is $n = 432 + 164 =596$

The number of offspring that is yellow peas is $y = 432$

The number of offspring that is green peas is $g = 164$

The sample proportion for offspring that are yellow peas is mathematically evaluated as

$\r p = \frac{ 164 }{596}$

$\r p = 0.275$

Given the the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = (100 - 95)\%$

$\alpha = 5\% = 0.0 5$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically evaluated as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\r p (1- \r p )}{n} }$

=> $E = 1.96 * \sqrt{\frac{0.275 (1- 0.275 )}{596} }$

=> $E = 0.0358$

The 95% confidence interval is mathematically represented as

$\r p - E < p < \r p + E$

=> $0.275 - 0.0358 < p < 0.275 + 0.0358$

=> $0.2392 < p < 0.3108$

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AfilCa [17]

<u>ANSWER</u>

The zeros are $x=-5,x=0,x=5$

EXPLANATION

Given;

$f(x)=x^4-25x^2$ .

We can rewrite the function as

$f(x)=x^2(x^2-25)$

$\Rightarrow f(x)=x^2(x^2-5^2)$

$\Rightarrow f(x)=x^2(x-5)(x+5)$

The zeros are found by equating the function to zero.

$\Rightarrow x^2(x-5)(x+5)=0$

$\Rightarrow (x-5)=0$

The multiplicity is 1, since it is odd the graph crosses at this intercept. which is $x=5$

Or

$\Rightarrow (x+5)=0$

The multiplicity is 1, since it is odd the graph crosses at this intercept. which is $x=-5$

Or

$\Rightarrow x^2=0$

This last root has a multiplicity of 2.

That is

$x=0$ repeats two times.

Since the multiplicity is even, the graph touches the x-axis at the point $x=0$ .

See graph.

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Ivenika [448]

Answer:

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240= 8 nights 180 minutes = 6 nights. Having a frequency helps determine patterns for book interest and study.

Step-by-step explanation:

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