Which polynomials are in standard form
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
From the information given,
Let the two digits that Chen writes down to be p and q
where,
q will be in the unit place and p will be in the tens place.
So, the value of the digit = 10p + q
So, if he swapped the number, he will have 10q + p
However,
the new number determined is thrice more than the 1/3 pf the original number.
i.e
the 1/3rd of the original number =
=
thrice more than that will be =
∴
multiply through by 3, we have :
10p+q + 9 = 30q + 3p
collecting the like terms, we have:
10p - 3p +q -30q +9 = 0
7p - 29q +9 = 0
7p - 29q = -9
Therefore, p,q lie between 0 and 9
Therefore, the possibility of the original number is p = 7 and q = 2
B=3; C=16; and E=4096.
Using the information we have gives us
We know that:
We know that 2³ = 8, so B = 3.
To "undo" a square root, we square the number; 4²=16, so C = 16.
To "undo" a fourth root, we raise the answer to the fourth power; 8⁴ = 4096, so E = 4096.
Using the information we have gives us
We know that:
We know that 2³ = 8, so B = 3.
To "undo" a square root, we square the number; 4²=16, so C = 16.
To "undo" a fourth root, we raise the answer to the fourth power; 8⁴ = 4096, so E = 4096.