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3 years ago

3. Which unit of measure would you use to measure the distance from Frisco to Dallas?

Mathematics

1 answer:

zalisa [80]3 years ago

3 0

Answer:

Miles/Kilometers

Step-by-step explanation:

Any long unit of measurement cuz its far away

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Can anybody help with this one ...... ?

VLD [36.1K]

Answer:The answer is choice 3

Step-by-step explanation:

8 0

2 years ago

A milk carton is 20cm long, 5cm wide and 40cm high. What volume of milk can it hold (in cubic cm)? *

Marina CMI [18]

Answer:

30 times 10 is 300. 300 times 50 is 15,000.

Step-by-step explanation:

bc i know

6 0

2 years ago

Read 2 more answers

Translate this sentence into an equation<br> 28 is the product of Julie score and two

pochemuha

Answer:

$2x=28$ ...Which is the required Equation.

Step-by-step explanation:

Question is

Translate this sentence into an equation

28 is the product of Julie score and two.

Solution:

Let the Julie score denoted by 'x'

According to the given condition,

28 is the product of Julie score and two

i.e 28 = 'x' × 2

$28=x\times 2\\\\2x=28$

$2x=28$ ...Which is the required Equation.

7 0

3 years ago

General solutions of sin(x-90)+cos(x+270)=-1<br> {both 90 and 270 are in degrees}

mixer [17]

Answer:

$\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

Step-by-step explanation:

Given:

$\sin (x-90^{\circ})+\cos(x+270^{\circ})=-1$

First, note that

$\sin (x-90^{\circ})=-\cos x\\ \\\cos(x+270^{\circ})=\sin x$

So, the equation is

$-\cos x+\sin x= -1$

Multiply this equation by $\frac{\sqrt{2}}{2}:$

$-\dfrac{\sqrt{2}}{2}\cos x+\dfrac{\sqrt{2}}{2}\sin x= -\dfrac{\sqrt{2}}{2}\\ \\\dfrac{\sqrt{2}}{2}\cos x-\dfrac{\sqrt{2}}{2}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos 45^{\circ}\cos x-\sin 45^{\circ}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos (x+45^{\circ})=\dfrac{\sqrt{2}}{2}$

The general solution is

$x+45^{\circ}=\pm \arccos \left(\dfrac{\sqrt{2}}{2}\right)+2\pi k,\ \ k\in Z\\ \\x+\dfrac{\pi }{4}=\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{4}\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

4 0

3 years ago

What is the value of the lower quartile?

murzikaleks [220]

Answer:

b.-4

Step-by-step explanation:

Because the lower quartile is the lower line on the box and whisker plot

6 0

2 years ago