<h2>
After 26.28 seconds projectile returns 26.28 seconds.</h2>
Explanation:
Initial velocity = 450 ft/s = 137.16 m/s
Angle, θ = 70°
Consider the vertical motion of projectile,
When the projectile return to the ground we have
Displacement, s = 0 m
Acceleration, a = -9.81 m/s²
Initial velocity, u = 137.16 x sin70 = 128.89 m/s
Substituting in s = ut + 0.5 at²
s = ut + 0.5 at²
0 = 128.89 x t + 0.5 x (-9.81) x t²
t² - 26.28 t = 0
t ( t- 26.28) = 0
t = 0 s or t = 26.28 s
After 26.28 seconds projectile returns 26.28 seconds.
Each planet has a different number of moons. Earth has only one, while planets like Mars have more (2). Even some planets have no moons (like Venus or Mercury).
Start by facing East. Your first displacement is the vector
<em>d</em>₁ = (225 m) <em>i</em>
Turning 90º to the left makes you face North, and walking 350 m in this direction gives the second displacement,
<em>d</em>₂ = (350 m) <em>j</em>
Turning 30º to the right would have you making an angle of 60º North of East, so that walking 125 m gives the third displacement,
<em>d</em>₃ = (125 m) (cos(60º) <em>i</em> + sin(60º) <em>j</em> )
<em>d</em>₃ ≈ (62.5 m) <em>i</em> + (108.25 m) <em>j</em>
The net displacement is
<em>d</em> = <em>d</em>₁ + <em>d</em>₂ + <em>d</em>₃
<em>d</em> ≈ (287.5 m) <em>i</em> + (458.25 m) <em>j</em>
and its magnitude is
|| <em>d</em> || = √[ (287.5 m)² + (458.25 m)² ] ≈ 540.973 m ≈ 541 m
Chemical bonds. These bonds form as a result of the sharing or exchange of electrons between the atoms
Answer:
a) E = 6.4 1019 J b) v = 0.69 10⁴4 m / s
Explication
a) convert E = 4.0 eV
1 eV = 1.6 10⁻¹⁹ J
E = 4.0 eV (1.6 10⁻¹⁹ J / 1 eV)
E = 6.4 10⁻¹⁹ J
b) Suppose we have a frontal shock and all the kinetic energy of oxygen is transferred to Cs
Ei = K = ½ m v²
Ef = 6.4 10⁻¹⁹ J
½ m v² = 6.4 10⁻¹⁹
The oxygen mass of the periodic table is
PA = 15,999 u
1u = 1.660 10⁻²⁷ kg
Pa = 15,999 1,660 10⁻²⁷ kg
m= Pa = 26,558 10⁻²⁷ kg
Let's calculate the speed
v2 = 2 / m 6.4 10⁻¹⁹
v2 = 2 / 26,558 10⁻²⁷ 6.4 10⁻¹⁹ =
v = √0.4819 10⁸
v = 0.69 10⁴4 m / s