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rodikova [14]
3 years ago
15

An infinite conducting cylindrical shell of outer radius r1 = 0.10 m and inner radius r2 = 0.08 m initially carries a surface ch

arge density σ = -0.35 μC/m2. A thin wire, with linear charge density λ = 1.1 μC/m, is inserted along the shells' axis. The shell and the wire do not touch and these is no charge exchanged between them.a) What is the new surface charge density, in microcoulombs per square meter, on the inner surface of the cylindrical shell?b) What is the new surface charge density, in microcoulombs per square meter, on the outer surface of the cylindrical shell?c) Enter an expression for the magnitude of the electric field ou

Physics
1 answer:
gayaneshka [121]3 years ago
8 0

Answer:

Explanation:

Solution is in the picture attached

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A golfer strikes her tee shot with the following velocities, vx = 106 m/s & vy = 66.2 m/s. a. What is the velocity of flight
lara [203]

Answer:

a) V ≈ 125 m/s;  b) Δt = 13.24 s;  c) ΔS ≈ 1450 m

Explanation:

a) We have just to calculate the vector resultant.

V² = 106² + 66.2²

V² = 15618.44

V ≈ 125 m/s

b) The time of flight is equal to the time to reach the maximum height summed to the time to reach the land.

In vertical:

V = V₀ + a * t

V = 66.2 - g * t

0 = 66.2 - 9.8 * t

t ≈ 6.76 s

So: Δt = 13.24 s

c) In horizontal:

V = ΔS / Δt

106 = ΔS / 13.52  ⇒  ΔS = 106 * 13.52

ΔS = 106 * 13.52

ΔS = 1433,12

ΔS ≈ 1450 m

3 0
1 year ago
If BHALA AHMAD KHAN applied the 20N force is applied on an object moving with the velocity 30 m/s. calculate the power in KW.
Leokris [45]

Answer:0.6kw

Explanation:

Power=force×velocity

Power=20×30=600w

In kw it's going to be 600/1000=0.6kw

4 0
3 years ago
Simplified. The absorption spectra of ions have been used to identify the presence of the elements in the atmospheres of the sun
Nookie1986 [14]

Answer:

The answer is "3.83 \times 10^9 \ m"

Explanation:

Z=2, so the equation is E= \frac{-4B}{n^2}

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The energy is the difference in transformation, name the energy delta E Deduct these two energies  

In this transition, the wavelength of the photon emitted is:

\Delta E=2.18 \times  10^{-18} ( \frac{1}{4}- \frac{1}{81})

\lambda = \frac{h c}{\Delta E}

h ( Planck's\  constant) = 6.62 \times  10^{(-34)} \ Js \\\\ speed \ of \ light = 3 \times 10^{8} \ \frac{m}{s}\\\\= \frac{6.62 \times 10^{(-34)} \times 3 \times 10^ {8}}{2.18 \times  10^{-18}} (\frac{1}{4}- \frac{1}{81}) \\\\=3.83 \times 10^9 \ m\\\\

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3 years ago
Which situation has the most potential energy
balu736 [363]

Answer:

B

Explanation: you are staying longr to jump 3 meters than one meter

4 0
3 years ago
What are two examples of acceleration???
atroni [7]

1. Jumping off a building

2. Hitting a tennis ball

3. Swinging a bucket of water in a circle

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3 years ago
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