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Kipish [7]
3 years ago
10

The neutron mass is 1.675 x 10-27 kg. Express the proton mass in eV/c, keeping 4 significant figures B) The mass of the electron

is 9.109 x 10-31 kg. Express this in eV/c . C) What is the mass of the hydrogen atom in eV/c??
Physics
1 answer:
VladimirAG [237]3 years ago
6 0

Answer:

Explanation:

given,

mass of neutron = 1.675 × 10⁻²⁷ kg

1 kg =  5.58 × 10³⁵ eV/c²                                        

a) mass of proton = 1.675 × 10⁻²⁷ ×  5.58 × 10³⁵ = 9.34 × 10⁸ eV/c²

b) mass of electron = 9.109 x 10⁻³¹ × 5.58 × 10³⁵ = 5.08 × 10⁵eV/c²

c) mass of hydrogen = 1.675 × 10⁻²⁷  × 5.58 × 10³⁵ = 9.34 × 10⁸ eV/c²

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hello your question is incomplete attached below is the complete question

answer :

20.16 v

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2 years ago
If earth's mass were half its actual value but its radius stayed the same, the escape velocity of earth would be:________
siniylev [52]

If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be V_e = \sqrt{\dfrac{GM}{r}}.

<h3>What is an escape velocity?</h3>

The ratio of the object's travel distance over a specific period of time is known as its velocity. As a vector quantity, the velocity requires both the magnitude and the direction. the slowest possible speed at which a body can break out of the gravitational pull of a certain planet or another object.

The formula to calculate the escape velocity of earth is given below:-

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Given that earth's mass was half its actual value but its radius stayed the same. The escape velocity will be calculated as below:-

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V_e = \sqrt{\dfrac{GM}{r}}.

Therefore, If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be V_e = \sqrt{\dfrac{GM}{r}}.

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brainly.com/question/14042253

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