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Andrew [12]
3 years ago
6

Please answer this question

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
8 0
The area of the base (six triangles with a base 15m and a height 7.5√3m):

A_B=6\cdot\dfrac{1}{2}\cdot15\cdot7.5\sqrt3\approx585\ m^2

The area of side walls (six triangles with a base 15m and a height 12m)

A_W=6\cdot\dfrac{1}{2}\cdot15\cdot12=540\ m^2

The surface area:

A_B+A_W=585+540=1,125\ m^2



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In this problem, there are two congruent right triangles: triangle XCA and triangle XBC, where the hypotenuse are XA and XB respectively. Considering triangle XBC, XB = radius = 17, and BC = 30 / 2 = 15. By pythagorean theorem, XC = sqrt(17^2 - 15^2) = sqrt(289 - 225) = sqrt(64) = 8 units.

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