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Andrew [12]
3 years ago
6

Please answer this question

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
8 0
The area of the base (six triangles with a base 15m and a height 7.5√3m):

A_B=6\cdot\dfrac{1}{2}\cdot15\cdot7.5\sqrt3\approx585\ m^2

The area of side walls (six triangles with a base 15m and a height 12m)

A_W=6\cdot\dfrac{1}{2}\cdot15\cdot12=540\ m^2

The surface area:

A_B+A_W=585+540=1,125\ m^2



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A ball is dropped from a height of 8 feet. If every time it bounces, it bounces 60% of its previous height, what is the total di
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Answer:

<h3>20feet</h3>

Step-by-step explanation:

Initial height of the ball = 8feet

If it bounces 60% of its previous height, its new height will be;

60% of 8

= 60/100 * 8

= 480/100

= 4.8 ft

If it bounces 60% of its current distance, new height will be expressed as;

60% of 4.8

= 0.6 * 4.8

= 2.88

The height of the ball will keep reducing and form a geometric progression of the form 8, 4.8, 2.88...

In order to get the total distance traveled by the ball, we need to calculate the sum to infinity of the sequence;

S∞ = a/1-r where;

a is the first term = 8

r is the common ratio

r = \frac{4.8}{8} = \frac{2.88}{4.8}\\r =  0.6

Substitute into the formula;

S∞ = a/1-r

S∞ = 8/1-0.6

S∞ = 8/0.4

S∞ = 20feet

Hence the total distance traveled by the ball is 20feet

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