Answer:72 pi
Step-by-step explanation:
just did the question.
Check where the first-order partial derivatives vanish to find any critical points within the given region:
![f(x,y)=2x^3+y^4\implies\begin{cases}f_x=6x^2=0\\f_y=4y^3=0\end{cases}\implies(x,y)=(0,0)](https://tex.z-dn.net/?f=f%28x%2Cy%29%3D2x%5E3%2By%5E4%5Cimplies%5Cbegin%7Bcases%7Df_x%3D6x%5E2%3D0%5C%5Cf_y%3D4y%5E3%3D0%5Cend%7Bcases%7D%5Cimplies%28x%2Cy%29%3D%280%2C0%29)
The Hessian for this function is
![\mathbf H(x,y)=\begin{bmatrix}f_{xx}&f_{xy}\\f_{yx}&f_{yy}\end{bmatrix}=\begin{bmatrix}12x&0\\0&12y^2\end{bmatrix}](https://tex.z-dn.net/?f=%5Cmathbf%20H%28x%2Cy%29%3D%5Cbegin%7Bbmatrix%7Df_%7Bxx%7D%26f_%7Bxy%7D%5C%5Cf_%7Byx%7D%26f_%7Byy%7D%5Cend%7Bbmatrix%7D%3D%5Cbegin%7Bbmatrix%7D12x%260%5C%5C0%2612y%5E2%5Cend%7Bbmatrix%7D)
with
, so unfortunately the second partial derivative test fails. However, if we take
we see that
for different values of
; if we take
we see
takes on both positive and negative values. This indicates (0, 0) is neither the site of an extremum nor a saddle point.
Now check for points along the boundary. We can parameterize the boundary by
![(x,y)=(8\cos t,8\sin t)](https://tex.z-dn.net/?f=%28x%2Cy%29%3D%288%5Ccos%20t%2C8%5Csin%20t%29)
with
. This turns
into a univariate function
:
![F(t)=f(8\cos t,8\sin t)=2^{10}\cos^3t+2^{12}\sin^4t](https://tex.z-dn.net/?f=F%28t%29%3Df%288%5Ccos%20t%2C8%5Csin%20t%29%3D2%5E%7B10%7D%5Ccos%5E3t%2B2%5E%7B12%7D%5Csin%5E4t)
![\implies F'(t)=3\cdot2^{10}\cos^2t(-\sin t)+2^{14}\sin^3t\cos t=2^{10}\sin t\cos t(16\sin^2t-3\cos t)](https://tex.z-dn.net/?f=%5Cimplies%20F%27%28t%29%3D3%5Ccdot2%5E%7B10%7D%5Ccos%5E2t%28-%5Csin%20t%29%2B2%5E%7B14%7D%5Csin%5E3t%5Ccos%20t%3D2%5E%7B10%7D%5Csin%20t%5Ccos%20t%2816%5Csin%5E2t-3%5Ccos%20t%29)
![F'(t)=0\implies\begin{matrix}\sin t=0\implies t=0,\,t=\pi\\\\\cos t=0\implies t=\dfrac\pi2,\,t=\dfrac{3\pi}2\\\\16\sin^2t-3\cos t=0\implies t=2\tan^{-1}\sqrt{\dfrac{\sqrt{1033}-32}3},\,t=2\pi-2\tan^{-1}\sqrt{\dfrac{\sqrt{1033}-32}3}\end{matrix}](https://tex.z-dn.net/?f=F%27%28t%29%3D0%5Cimplies%5Cbegin%7Bmatrix%7D%5Csin%20t%3D0%5Cimplies%20t%3D0%2C%5C%2Ct%3D%5Cpi%5C%5C%5C%5C%5Ccos%20t%3D0%5Cimplies%20t%3D%5Cdfrac%5Cpi2%2C%5C%2Ct%3D%5Cdfrac%7B3%5Cpi%7D2%5C%5C%5C%5C16%5Csin%5E2t-3%5Ccos%20t%3D0%5Cimplies%20t%3D2%5Ctan%5E%7B-1%7D%5Csqrt%7B%5Cdfrac%7B%5Csqrt%7B1033%7D-32%7D3%7D%2C%5C%2Ct%3D2%5Cpi-2%5Ctan%5E%7B-1%7D%5Csqrt%7B%5Cdfrac%7B%5Csqrt%7B1033%7D-32%7D3%7D%5Cend%7Bmatrix%7D)
At these critical points, we get
![F(0)=1024](https://tex.z-dn.net/?f=F%280%29%3D1024)
![F\left(2\tan^{-1}\sqrt{\dfrac{\sqrt{1033}-32}3}\right)\approx893](https://tex.z-dn.net/?f=F%5Cleft%282%5Ctan%5E%7B-1%7D%5Csqrt%7B%5Cdfrac%7B%5Csqrt%7B1033%7D-32%7D3%7D%5Cright%29%5Capprox893)
![F\left(\dfrac\pi2\right)=4096](https://tex.z-dn.net/?f=F%5Cleft%28%5Cdfrac%5Cpi2%5Cright%29%3D4096)
![F(\pi)=-1024](https://tex.z-dn.net/?f=F%28%5Cpi%29%3D-1024)
![F\left(\dfrac{3\pi}2\right)=4096](https://tex.z-dn.net/?f=F%5Cleft%28%5Cdfrac%7B3%5Cpi%7D2%5Cright%29%3D4096)
![F\left(2\pi-2\tan^{-1}\sqrt{\dfrac{\sqrt{1033}-32}3}\right)\approx893](https://tex.z-dn.net/?f=F%5Cleft%282%5Cpi-2%5Ctan%5E%7B-1%7D%5Csqrt%7B%5Cdfrac%7B%5Csqrt%7B1033%7D-32%7D3%7D%5Cright%29%5Capprox893)
We only care about 3 of these results.
![t=\dfrac\pi2\implies(x,y)=(0,8)](https://tex.z-dn.net/?f=t%3D%5Cdfrac%5Cpi2%5Cimplies%28x%2Cy%29%3D%280%2C8%29)
![t=\pi\implies(x,y)=(-8,0)](https://tex.z-dn.net/?f=t%3D%5Cpi%5Cimplies%28x%2Cy%29%3D%28-8%2C0%29)
![t=\dfrac{3\pi}2\implies(x,y)=(0,-8)](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B3%5Cpi%7D2%5Cimplies%28x%2Cy%29%3D%280%2C-8%29)
So to recap, we found that
attains
- a maximum value of 4096 at the points (0, 8) and (0, -8), and
- a minimum value of -1024 at the point (-8, 0).
The question is asking to calculate the magnitude of the acceleration due to gravity on the planet and base on the given of the problem and in my further calculation, the magnitude would be 3.638 m/s^2. I hope you are satisfied with my answer and feel free to ask for more
Answer:
theta= 1.085
Step-by-step explanation:
Answer:
3/20=6/40=15/100
Step-by-step explanation:
Multiply 3 by 2 to figure out the numerator for /40 and multiply 20 by 5 to figure out the denominator of 15/