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malfutka [58]
3 years ago
10

Which of the following options is a 3rd degree polynomial with exactly 1 real

Mathematics
1 answer:
lidiya [134]3 years ago
5 0

Answer:D

Step-by-step explanation:

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-12 is equal to a number subtracted from 3
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3 - 15  =  -12
so that is your answer
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Devon uses the equation c = 9.74...
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How is 2 weeks for quick

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The profit p ( in hundreds of dollars ) that a company makes depends on the expenditure x ( in hundreds of dollars ) that the co
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Answer:

Expenditure x (in hundreds of dollars) = $2,000

Step-by-step explanation:

Given:

Profit p (in hundreds of dollars)

Expenditure x (in hundreds of dollars)

p(x) = -0.5x² + 20x + 23

Find:

Expenditure for advertising .

Computation:

x = -(Cofficient of x) / 2(Cofficient of x²)

x = -(20) / 2(-0.5)

x =  20

Expenditure x (in hundreds of dollars) = 20 × $100

Expenditure x (in hundreds of dollars) = $2,000

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Line AB contains points A (−3, 5) and B (−3, 3). Line AB has a slope that is
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A scuba diver dove from the surface of the ocean to an elevation of -79 9/10 feet at a rate of -21.3 per minute. After spending
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Answer:

The rate of change of the divers elevation is approximately 24.71 feet/minute

Step-by-step explanation:

The given information are;

The depth to which the scuba diver dove =-79\frac{9}{10} \ feet

The rate at which he dove = -21.3 feet/minute

The time which he spent at that elevation = 10.5 minutes

The elevation the diver then ascended to = -8\frac{9}{10} \ feet

The total time for the dive = 17\frac{1}{8} \ minutes

Therefore, the time, t_d, with which the scuba diver descended to -79\frac{9}{10} \ feet is given as follows;

t_d = \dfrac{Distance}{Speed} = \dfrac{-79\frac{9}{10} }{-21.3} \approx 3.75 \  minutes

The time, t_e, it took the scuba diver to elevate to -8\frac{9}{10} \ feet is given as follows;

t_e = 17\frac{1}{8} \ minutes - (3.75 + 10.5) minutes ≈ 2.8738 minutes

The rate of change of the divers elevation = (Final elevation - Initial elevation)/(Time taken)

∴ The rate of change of the divers elevation = (-8\frac{9}{10} \ feet - (-79\frac{9}{10} \ feet ))/(2.87 minutes) = 71/2.8738 ≈ 24.71 feet/minute to the nearest hundredth

The rate of change of the divers elevation ≈ 24.71 feet/minute.

8 0
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