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3 years ago

Which of the following options is a 3rd degree polynomial with exactly 1 real

Mathematics

1 answer:

lidiya [134]3 years ago

5 0

Answer:D

Step-by-step explanation:

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Using the expansion

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Please help ASAP

REY [17]

<h3><u>Answer :</u><u>-</u><u> </u></h3>

<h3><u>Question :- </u></h3>

$find \: \frac{ - 4}{5} \times \frac{3}{7} \times \frac{15}{16} \times ( \frac{ - 14}{9} )$

<h2><u>Solution :- </u></h2>

<h3><u>First </u><u>way:</u></h3>

$\frac{ - 4}{5} \times \frac{3}{7} \times \frac{15}{16} \times ( \frac{ - 14}{9} )$

$= > \: ( - \frac {4 \times 3}{5 \times 7} ) \times ( \frac{15 \times ( - 14)}{16 \times 9}$

$= > \: \frac{ - 12}{35} \times ( \frac{ - 35}{24} ) = \frac{ - 12 \times ( - 35)}{35 \times 24} = \frac{1}{2}$

<h3><u>Second way : </u></h3>

$\frac{ - 4}{5} \times \frac{3}{7} \times \frac{15}{16} \times (\frac{ - 14}{9} )$

$= > \: ( \frac{ - 4}{5} \times \frac{15}{16} ) \times \binom{3}{7} \times ( \frac{ - 14}{9} )$

[ ↑ Using commutativity and Associativity ] ...

$\frac{ - 3}{4} \times ( \frac{ - 2}{3} ) = \frac{1}{2}$

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3 years ago