All categories

3 years ago

Describe what a finite graph is and give an example of how a finite graph would be used to represent something.

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

8 0

Answer:

A graph with a set amount of numbers.

Step-by-step explanation:

Infinite means never ending and that's what most graphs are. But, a finite graph is a graph that doesn't have arrows at the end of the lines. (simplified answer) A better way of saying it is a graph with a fixed starting position and a fixed ending position. You can use this type of graph if you don't want to go over or under a certain value.

Hope this helps!

You might be interested in

Mary throws her Grandma’s favorite crystal dish out the second floor window, which is 6 meters from the ground. She is really up

wlad13 [49]

we know that

acceleration due to gravity is 9.8m/s^2

so, we get

$a(t)=9.8$

and acceleration will always be constant

we know that

integral of acceleration is velocity

so, we can integrate both sides

$\int \:a\left(t\right)dt=\int \:9.8dt$

$v(t)=9.8t+C$

we are given

v(0)=35m/s

we can use it and find C

$v(0)=9.8*0+C$

$35=9.8*0+C$

$C=35$

now, we can plug it back

$v(t)=9.8t+35$

we know that

integral of velocity is height

we can integrate it again

$\int \:v\left(t\right)dt=\int \:\left(9.8t+35\right)dt$

$s(t)=\int \:\left(9.8t+35\right)dt$

$s(t)=4.9t^2+35t+C$

now, we have

s(0)=6

we can use it and find C

$s(0)=4.9(0)^2+35(0)+C$

$6=4.9(0)^2+35(0)+C$

now, we can plug back C

$C=6$

and we get

$s(t)=4.9t^2+35t+6$ .............Answer

4 0

3 years ago

Read 2 more answers

A plane is descending into the airport. After 5 minutes it is at a height of 6500 feet. After 7 minutes it is at a height of 590

Jet001 [13]

Let's assume

height of plane in feet =h

time in minutes =t

we are given

A plane is descending into the airport. After 5 minutes it is at a height of 6500 feet

so, we get one point as (5,6500)

After 7 minutes it is at a height of 5900 feet

so, we get another point as (7,5900)

we can use point slope form of line

$y-y_1=m(x-x_1)$

points as

(5,6500)

x1=5, y1=6500

(7,5900)

x2=7 , y2=5900

Calculation of slope(m):

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug values

$m=\frac{5900-6500}{7-5}$

$m=-300$

Equation of line:

we can use formula

$y-y_1=m(x-x_1)$

we can plug values

$h-6500=-300(t-5)$

$h=-300t+8000$

Time of landing:

we can set h=0

and then we can solve for t

$h=-300t+8000=0$

$t=\frac{80}{3}min$ ..............Answer

5 0

3 years ago

Answer #5,6,7,8,9,10

MatroZZZ [7]

$5)\ -2\times\frac{3}{7}=-\frac{2\times3}{7}=-\frac{6}{7}\\\\6)\ -2\frac{2}{3}\times4\frac{1}{10}=-\frac{8}{3}\times\frac{41}{10}=-\frac{4}{3}\times\frac{41}{5}=-\frac{164}{15}=-10\frac{14}{15}\\\\7)\ -2\frac{1}{5}\times(-1\frac{3}{4})=-\frac{11}{5}\times(-\frac{7}{4})=\frac{77}{20}=3\frac{17}{20}\\\\8)\ -1\frac{1}{4}\times9=-\frac{5}{4}\times9=-\frac{45}{4}=-11\frac{1}{4}\\\\9)\ -1\frac{5}{7}\times(-2\frac{1}{2})=-\frac{12}{7}\times(-\frac{5}{2})=\frac{6}{7}\times\frac{5}{1}=\frac{30}{7}=4\frac{2}{7}$

$1)\ -2\frac{3}{8}\times2\frac{1}{2}=-\frac{19}{8}\times\frac{5}{2}=-\frac{95}{16}=-5\frac{15}{16}$

7 0

3 years ago

Read 2 more answers

P is a rectangle with a length 40 cm and width x cm

TiliK225 [7]

The first thing we must do for this case is to look for the area of each rectangle.
We have then:
A1 = (40) * (x)
A2 = (1.25 * 40) * (y)
Then, we have the following relationship between areas:
"the area of Q is 10% less than the area of p"
A2 = 0.9 * A1
Substituting values we have:
(1.25 * 40) * (y) = 0.9 * ((40) * (x))
We rewrite:
50y = 36x
The relationship x: y is:
x / y = (50) / (36)
Simplifying:
x / y = (25) / (18)
Answer:
the ratio of x:y is:
25:18

3 0

3 years ago

A line passes through (8,-4) and has slope 2/3. What is an equation in point slope form of the line? An equation of the line is?

QveST [7]

Answer:

The point slope form of the line would be y + 4 = 2/3(x - 8) and the equation of the line would be y = 2/3x - 28/3

Step-by-step explanation:

To find the point-slope form of the line, start with the base form of point-slope form. Then input the point we have and the slope in the appropriate places.

y - y1 = m(x - x1)

y - -4 = 2/3(x - 8)

y + 4 = 2/3(x - 8)

Now to find the slope intercept form, you simply need to solve for y.

y + 4 = 2/3(x - 8)

y + 4 = 2/3x - 16/3

y = 2/3x - 28/3

3 0

3 years ago