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Firdavs [7]
2 years ago
13

Which of the following best describes the graph below?

Mathematics
1 answer:
scoundrel [369]2 years ago
4 0

Answer:

B

Step-by-step explanation:

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Simplify the Following: <br>⅔ + 2³ - ⅓<br><br>a.) 6 ⅓ <br>b.) 8 ⅓<br>c.) ⁷/2 <br>d.) -6​
allochka39001 [22]

Answer:

B

Step-by-step explanation:

You have to evaluate the power and calculate the sum or difference in order to get the answer

7 0
3 years ago
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What is the sum of the counting numbers 1 - 40
AVprozaik [17]
Simply it as follows:

1 + 39 = 40
2 + 38 = 40 etc

18 + 22 = 40
19 + 21 = 40

There are 19 of these plus 40 itself . . .therefore 20 of them

20 x 40 = 800

And finally the last number not used, 20

Therefore 800 + 20 = 820
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3 years ago
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The zeros of the function f(x) =(x+2) to the second power minus 5
pashok25 [27]
(x+2)^2-5=0\\&#10;(x+2)^2=5\\&#10;x+2=-\sqrt5 \vee x+2=\sqrt5\\&#10;x=-2-\sqrt5 \vee x=-2+\sqrt5
8 0
3 years ago
Help, please the question and thank you
Fynjy0 [20]

Answer:

2

Step-by-step explanation:

If A = (2, 3) then a dilation of scale factor 2 means that the x and y coordinates are multiplied by 2, so x = 2 x 2 = 4  and y = 3 x 2 = 6, so A' = (4, 6)

8 0
2 years ago
4. Andrés desea embaldosar el piso de su casa que tiene 375 cm de ancho y 435 cm de largo. Calcula la longitud del lado que tend
svetlana [45]

Answer:

Sabemos que el piso es un rectángulo de 435 cm de largo y 375 cm de ancho.

Recordar que para un rectángulo de largo L, y ancho W, el área es:

A = L*W

Entonces el área del piso, será:

A = 435cm*375cm = 163,125 cm^2

Primero, sabemos que se utilizaran baldosas (las cuales son cuadradas) y queremos saber la longitud de lado que tendrían las baldosas.

No tenemos ningún criterio para encontrar este lado, solo que (si queremos usar un número entero de baldosas) el largo L del lado de la baldosa deberá ser un divisor de tanto el ancho como el largo del suelo.

Dicho de otra forma

el largo, 435cm, tiene que ser múltiplo de L

el ancho, 375cm, tiene que ser múltiplo de L.

Por ejemplo, ambos números son múltiplos de 5, entonces podríamos tomar L = 5cm

En este caso, el área de cada baldosa es:

a = L^2 = 5cm*5cm = 25cm^2

Y el número total de baldosas que necesitaría usar esta dado por el cociente entre el área del suelo y el area de cada baldosa.

N = ( 163,125 cm^2)/(25cm^2) = 6,525 baldosas.

También sabemos que ambos números (435cm y 375cm) son múltiplos de 15cm

Entonces las baldosas podrían tener 15cm de lado.

En este caso, el área de cada baldosa es:

A = (15cm)^2 = 225cm

En este caso el número total de baldosas necesarias será:

N =  ( 163,125 cm^2)/(225cm^2) = 725 baldosas.

5 0
3 years ago
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