Hello :
y = 3x²+9x
= 3(x² + 3x )
= 3 ( x² +2(3/2)x +(3/2)²) -(3/2)²)
= 3((x+3/2)² -9/4)
y = 3 (x+3/2)² -27/4
<span>the x-coordinate of the vertex is : - 3/2</span>
The third answer choice; right triangle.
Start your dot on 3 on the y axis. Move is downwards on the y axis by 5 everytime you move over once on the x axis. Shade all the stuff above the line since it says y is greater than -5x+3
Step one: Do half of 28. So now you know what one hour is okay.
Step two: You now know three hours is 42 stops
Step Three: total amount in 4 hours 28 times 2 and that is 56 stops
Hopes this helps mate
Problem 7)
The answer is choice B. Only graph 2 contains an Euler circuit.
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To have a Euler circuit, each vertex must have an even number of paths connecting to it. This does not happen with graph 1 since vertex A and vertex D have an odd number of vertices (3 each). The odd vertex count makes it impossible to travel back to the starting point, while making sure to only use each edge one time only.
With graph 2, each vertex has exactly two edges attached to it. So an Euler circuit is possible here.
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Problem 8)
The answer is choice B) 5
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Work Shown:
abc base 2 = (a*2^2 + b*2^1 + c*2^0) base 10
101 base 2 = (1*2^2 + 0*2^1 + 1*2^0) base 10
101 base 2 = (1*4 + 0*2 + 1*1) base 10
101 base 2 = (4 + 0 + 1) base 10
101 base 2 = 5 base 10
