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3 years ago

Pleaseee helpppp:)))

Mathematics

1 answer:

matrenka [14]3 years ago

5 0

Answer:

<h2>Option B:</h2><h3>112 families </h3>

Step-by-step explanation:

Given,

No. of families = 75

Out of 75 no. of families had cars = 42

Out of 1, no. of families can have cars

$= \frac{42}{75}$

Therefore, 

Out of 200 families, no. of families had cars

$= 200 \times \frac{42}{75}$

$=200 \times \frac{14}{25}$

= 8 × 14

= 112

Hence, 

option B is correct as 112 families have cars out of 200 families (Ans)

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postnew [5]

Answer:

it's is a

because the law states

5 0

3 years ago

Read 2 more answers

PQRS is a parallelogram. Find the values of a and b. Solve for the value of c if c = a + b.

Alecsey [184]

Answer:

a = 7

b = 7

c = 14 [Correct option is B. 14]

Step-by-step explanation:

Since the shape is a parallelogram, to solve this problem, use some of the properties of a parallelogram:

(i) Opposite sides are parallel and congruent. Being congruent means the sides are identical. In other words, they have the same length.

From the diagram, this means that sides PQ and SR are identical. i.e

=> PQ = SR

=> 6a + 10 = 8a - 4 [collect like terms and solve]

=> 14 = 2a

=> a = 7

(ii) Opposite angles are congruent. Angles PQR and PSR are identical. i.e

<PQR = <PSR = (9b + 2)°

Also,

<SPQ = <SRQ = (18b - 11)°

(iii) Consecutive angles are supplementary. The sum of any two angles that are not opposite to each other is 180°. i.e.

<SPQ + <PQR = 180°

<PQR + <QRS = 180°

<QRS + <RSP = 180°

Also,

<PSR + <SPQ = 180°

(9b + 2)° + (18b - 11)° = 180° [expand bracket and solve for b]

9b + 2 + 18b - 11 = 180

27b - 9 = 180

27b = 189

b = 7

Now, since a = 7 and b = 7;

c = a + b = 7 + 7 = 14

Therefore;

a = 7

b = 7

c = 14

8 0

4 years ago

The audince thinks 30%of brandons jokes are funny what fraction does the audince think are funny

liq [111]

Answer:

Let Brandon's joke be X . Audience like 30% of X. So... 30/100 of X which gives 3/10 of X.

Step-by-step explanation:

4 0

3 years ago

Three fourths of 9.30

Marianna [84]

3/4 of 9.3

3 ÷ 4 = 0.75

0.75 × 9.30 = 6.975

therefore the answer is 6.975

6 0

3 years ago

Hypothesis Testing

Yuri [45]

Answer:

Problem 1: We conclude that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement.

Problem 2: We conclude that the volume of Google stock has changed.

Step-by-step explanation:

Problem 1:

We are given that in a recent survey conducted by Pew Research, it was found that 156 of 295 adult Americans without a high school diploma were worried about having enough saved for retirement.

Let p = proportion of adult Americans without a high school diploma who are worried about having enough saved for retirement

So, Null Hypothesis, $H_0$ : p $\leq$ 50% {means that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement}

Alternate Hypothesis, $H_A$ : p > 50% {means that a majority of adult Americans without a high school diploma are worried about having enough saved for retirement}

This is a right-tailed test.

The test statistics that would be used here is One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of adult Americans who were worried about having enough saved for retirement = $\frac{156}{295}$ = 0.53

n = sample of adult Americans = 295

So, the test statistics = $\frac{0.53-0.50}{\sqrt{\frac{0.50(1-0.50)}{295} } }$

= 1.03

The value of z-test statistics is 1.03.

Also, the P-value of the test statistics is given by;

P-value = P(Z > 1.03) = 1 - P(Z $\leq$ 1.03)

= 1 - 0.8485 = 0.1515

Now, at a 0.05 level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is less than the critical value of z as 1.03 < 1.645, so we insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement.

Problem 2:

We are given that a random sample of 35 trading days in 2014 resulted in a sample mean of 3.28 million shares with a standard deviation of 1.68 million shares.

Let $\mu$ = mean daily volume in Google stock

So, Null Hypothesis, $H_0$ : $\mu$ = 5.44 million shares {means that the volume of Google stock has not changed}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ 5.44 million shares {means that the volume of Google stock has changed}

This is a two-tailed test.

The test statistics that would be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean volume in Google stock = 3.28 million shares

s = sample standard deviation = 1.68 million shares

n = sample of trading days = 35

So, the test statistics = $\frac{3.28-5.44}{\frac{1.68}{\sqrt{35} } }$ ~ $t_3_4$

= -7.606

The value of t-test statistics is -7.606.

Also, the P-value of the test statistics is given by;

P-value = P( $t_3_4$ < -7.606) = Less than 0.05%

Now, at a 0.05 level of significance, the t table gives a critical value of -2.032 and 2.032 at 34 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, so we sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the volume of Google stock has changed.

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3 years ago