Width of the rectangle is 9 units
Step-by-step explanation:
- Step 1: Let the width of the rectangle be x. Then the length = x - 3. Find dimensions of the rectangle if its area = 54 sq. units
Area of the rectangle = length × width
54 = x (x - 3)
54 = x² - 3x
x² - 3x - 54 = 0
x² + 6x - 9x - 54 = 0 (Using Product Sum rule to factorize)
x(x + 6) - 9(x + 6) = 0
(x + 6)(x - 9) = 0
x = -6, 9 (negative value is neglected)
x = 9 units
The answer is 20. you'll have to multiply 10 times 3 and get 30. Then you'll subtract the 10 from the 30 and get 20
Roots: - √5 , √5, and - 3
=> these are factors of the polynomial: (x + √5), (x - √5), and (x + 3).
Multiply those three factors:
(x + √5) (x - √5) ( x + 3) = [x^2 - 5] ( x + 3 ) = x^2 + 3x^2 - 5x - 15
Therefore the polynomial x^2 + 3x^2 - 5x - 15 is a polynomial with the given roots.
Answer: option B. x^3 + 3x^2 - 5x - 15
Answer:
the surface area should be 544 (whatever the unit is)
Step-by-step explanation:
You start by taking the rectangles on the side and finding their area.
1. (10×14)×2 ←Because there are two rectanglular sides.
2. find the area of the triangles on the side. 1/2bh = area of triangle.
(.5×8×6)×4 ← in order to find the area for all of the triangles.
3. lastly take the base of the prism and find the area then add the previously found values together.
(12×14)+(.5×8×6)×4+ (10×14)×2 = 544
