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xz_007 [3.2K]
3 years ago
14

Write three equivalent ratios for each ratio 18/6 , 5/45 , 3/5

Mathematics
2 answers:
xxTIMURxx [149]3 years ago
7 0
18/6 = 3/1 = 6/2 = 9/3

5/45 = 1/9 = 2/18 = 3/27

3/5 = 6/10 = 9/15 = 12/20
cricket20 [7]3 years ago
7 0
18/6=6/2, 3/1, 36/12
5/45=1/9, 10/90, 20/180
3/5=15/25, 6/10, 24/40
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ioda

Answer:

55= 1, 5, 11 and 55

3= 1,3

66= 1, 2, 3, 6, 11, 22, 33, 66

Step-by-step explanation:

you just need to find the multiplacation to eah number

6 0
3 years ago
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Two rectangles are similar . The first rectangle is 14 units long and 6 units wide . The second rectangle is 22.4 units long and
DaniilM [7]

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Step-by-step explanation:

4 0
3 years ago
PLEASE HELP
kolbaska11 [484]

Answer:

  • a) P(x) = 32000*1.04^x
  • b) $37435
  • c) During year 7

Step-by-step explanation:

<u>Given</u>

  • Initial pay = $32000
  • Increase rate = 4%

a. <u>Formula</u>

  • P(x) = 32000*1.04^x

b. Year 5 is after 4 years, so we are looking for the value of P(4)

  • P(4) = $32000*1.04^4 = $37435

c. <u>P(x) = 40000, x = ?</u>

  • 40000 = 32000*1.04^x
  • 1.04^x = 40000/32000
  • 1.04^x = 1.25
  • log 1.04^x = log 1.25
  • x = log 1.25 / log 1.04
  • x = 5.69, this is 6 years after

The required number of the years is 6 + 1 = 7

3 0
3 years ago
I need help with this . short and easy response please
Alika [10]
\frac{\frac{1}{4}-\frac{2}{3}}{\frac{3}{5}}=\frac{\frac{3}{12}-\frac{8}{12}}{\frac{3}{5}}=\text{ }\frac{-\frac{5}{12}}{\frac{3}{5}}=\text{ -}\frac{25}{36}

7 0
1 year ago
The total surface area of this cuboid is 112cm squared find the value of x
Liono4ka [1.6K]

Answer:

The height of cuboid is 3 cm

Step-by-step explanation:

Total surface area of cuboid  = 2lb+2bh+2hl

Length of cuboid = 10 cm

Width of cuboid = 2 cm

Let the height be x

Total surface area of cuboid  = 2(10)(2)+2(2)(x)+2(x)(10)

Total surface area of this cuboid is 112 cm squared

 2(10)(2)+2(2)(x)+2(x)(10)=112

40+4x+20x=112

40+24x=112

24x=112-40

24x=72

x=\frac{72}{24}

x=3

Hence the height of cuboid is 3 cm

5 0
3 years ago
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