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babymother [125]
3 years ago
13

A tablet and a digital camcorder are both on sale for 30% off. The regular price of the tablet is $185. The regular price of the

camcorder is $140. What is the sale price of the tablet?
Mathematics
1 answer:
Arlecino [84]3 years ago
3 0

Answer:

129.50

Step-by-step explanation:

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An article retails for 27.50. The city sales tax is 6%, and the federal excise tax is 8%. How much does the article cost altoget
-Dominant- [34]
Cost of the article = $27.50
Amount of city sales tax = (27.50 x 6%) = $1.65
Amount of excise tax = (27.50 x 8%) = $2.20
From my knowledge, we pay city sales tax and federal excise tax when we buy something, so the total cost would be $31.35
5 0
3 years ago
Read 2 more answers
Pls help fast I am dumb and I need to go to 2 competitions today!!!
aliina [53]

Answer:0.25

Step-by-step explanation:

Just type it in a calculator

3 0
4 years ago
Read 2 more answers
Remember to show work and explain. Use the math font.
MrMuchimi

Answer:

\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}

Step-by-step explanation:

\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================

1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}

\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)

--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)

--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}

6 0
3 years ago
Can someone please help me answer these 6 questions?
Mamont248 [21]
1) 19.25

2) 12.92

3) 25.20

4) 19.68

5) 77.05

6)81.67
8 0
4 years ago
Given x = 5, y = -6, z = -2, evaluate z - yx
Andreyy89

Answer: 28

Step-by-step explanation: Plugging them in, it would be -2 - (-6)(5).

- 2 - (-30)

-2 + 30

28

8 0
3 years ago
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