Hello
Your answer is $310.84
Hope this helps!
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Note: Consider the side of first triangle is TQ instead of TA.
Given:
Triangles TQM and TPN which share vertex T.
![TQ\cong TP,TM\cong TN](https://tex.z-dn.net/?f=TQ%5Ccong%20TP%2CTM%5Ccong%20TN)
To find:
The theorem which shows that
.
Solution:
In triangle TQM and TPN,
[Given]
[Given]
[Given]
Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.
[SAS]
Therefore, the correct option is C.
Answer: D) 52%
Step-by-step explanation:
G = gymnastics
B = baseball
S = soccer
G = 28%
BA = 29%
S = 19%
G and BA = 14%
BA and S = 12%
G and S = 10%
GBS = 8%
So, as we can see at the Venn diagram attached (consider every number in %)
GBS = 8
A = G and S - GBS = 10 - 8 = 2
B = G and BA - GBS = 14 - 8 = 6
C = BA and S - GBS = 12 - 8 = 4
Only G = G - A - B - GBS = 28 - 2 - 6 - 8 = 12
Only BA = BA - B - C - GBS = 29 - 6 - 4 - 8 = 11
Only S = S - A - C - GBS = 19 - 2 - 4 - 8 = 5
So, 2+6+4+12+11+5+8 = 48
100 - 48 = 52%
Remember you can do anything to an equaiton as long asyou do it to both sides
4v+18≥6v+10
minus 4v both sides
4v-4v+18≥6v-4v+10
0+18≥2v+10
18≥2v+10
minus 10 both sides
18-10≥2v+10-10
8≥2v+0
8≥2v
divide both sides by 2
8/2=(2v)/2
4≥(2/2)v
4≥1v
4≥v
v≤4
There is 180 degrees in a triangle so it is 80 degrees