Answer:
American Roulette
1. The probability of losing a ’1st 12’ bet on a single spin is:
= 0.67
2. The probability of winning 7 out of the 10 total bets is:
= 0.23
Step-by-step explanation:
Possible outcomes in an American Roulette wheel = 38
Make-up of the outcomes = 18 black, 18 red and 2 green
Green outcomes are numbered 0 and 00
Number of wins for this person = 12
Probability of winning = 0.33 (12/36)
Number of possible losses for this person = 24
Probability of losing = 0.67 (24/36)
1. The probability of losing a '1st 12' bet on a single spin is:
= (36 - 12)/36
= 0.67
2. The probability of winning 7 out of the 10 total bets is:
Probability of winning = 12/36 * 7/10
= 0.23
The answer is B because it has one solution
Answer:
A. x = 1/2
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
- Terms/Coefficients
- Factoring
- Standard Form: ax² + bx + c = 0
- Solving quadratics
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
4x² + 3 = 4x + 2
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Equality Property] Rewrite in standard form: 4x² - 4x + 1 = 0
- Factor: (2x - 1)² = 0
- Solve: x = 1/2
Answer:
<h2>
</h2>
Step-by-step explanation:
Hope it is helpful.....
