Charlie's puppy Max, weighs 6 pounds. How many ounces does Max weight?

Determine the total number of roots of each polynomial function using the factored form. f (x) = (x + 5)3(x - 9)(x + 1)

densk [106]

Answer:

Answer is 5

Step-by-step explanation:

Okay hun so let me tell u what's up here

They give us this equation and ask for the 'roots'

(x+5)^3(x-9)(x+1)

Now lemme tell you the roots of this one

-5, 9, -1

you get this from making each of them 0

The answer to this would be "3" because there are 3 roots, buT wait theRe'S mOre

(x+5) goes 3 times

So thy must recount it

-5, -5, -5, 9, -1 <-- These are the roots

that's 5 roots in total

....also I did this on edgen, got it right with 5

5 0

3 years ago

Read 2 more answers

Am i correct ? geometry problem

MrRa [10]

Unfortunately your response would only be true if CD was perpendicular to AB. However we don't know if CD is perpendicular or not. So we don't have enough information. The actual answer is choice E) None of these.

3 0

3 years ago

.Divide the sum of 13/5 and -12/7 by the product of -31/7 and -(1/2)

andre [41]

Answer:

hello u so cool i admire you <3

6 0

2 years ago

Read 2 more answers

If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how

Goryan [66]

Rates are used to measure a quantity over another.

The 1.8 million cars use $1.85 \times 10^{10}$ liters each year

Given

$Cars = 1.8\ million$

$d = 17500km$ --- distance

$r = 40miles/gallon$

First, we calculate the number (n) of gallons used by each car

$r = \frac{d}{n}$

Solve for n

$n = \frac{d}{r}$

So, we have:

$n = \frac{17500km}{40miles/gallon}$

$n = \frac{17500km}{40miles}gallon$

Convert miles to kilometers

$n = \frac{17500km}{40km \times 1.60934}gallon$

$n = \frac{17500km}{64.3738km}gallon$

$n = 271.85\ gallon$

The number of gallons (N), used by all the cars is:

$N = n \times cars$

$N = 271.85 \times 1.8\ million$

$N = 489330000$

Convert to liters

$N = 489330000 \times 3.78541L$

$N = 1852314675.3L$

In scientific notation to 2 decimal places, we have:

$N = 1.85 \times 10^{10}L$

Hence, the number of liters used is $1.85 \times 10^{10}$

Read more about distance and rates at:

brainly.com/question/24659604

4 0

3 years ago

At a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective pa

11Alexandr11 [23.1K]

Answer:

Probability that fewer than 2 of these parts are defective is 0.604.

Step-by-step explanation:

We are given that at a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective parts 19% of the time.

A random sample of 7 parts produced by this machine is chosen.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 7 parts

r = number of success = fewer than 2

p = probability of success which in our question is % of defective

parts produced by one of the machine, i.e; 19%

LET X = Number of parts that are defective

So, it means X ~ Binom(n = 7, p = 0.19)

Now, probability that fewer than 2 of these parts are defective is given by = P(X < 2)

P(X < 2) = P(X = 0) + P(X = 1)

= $\binom{7}{0}\times 0.19^{0} \times (1-0.19)^{7-0}+ \binom{7}{1}\times 0.19^{1} \times (1-0.19)^{7-1}$

= $1 \times 1 \times 0.81^{7} +7 \times 01.9^{1} \times 0.81^{6}$

= 0.604

Therefore, the probability that fewer than 2 of these parts are defective is 0.604.

8 0

2 years ago