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mr Goodwill [35]
3 years ago
10

Two customers go to a fast food restaurant the first customer buys two burgers and one french fry for $4.75 the second customer

buys three hamburgers and three french fries for nine dollars how much does each hamburger cost
Mathematics
1 answer:
Kazeer [188]3 years ago
6 0

Answer: $1.75

Step-by-step explanation:

Assume hamburgers are x and French fries are y.

Use a simultaneous equation to solve;

2x + y = 4.75

3x + 3y = 9.00

Using substitution;

2x + y = 4.75

y = 4.75 - 2x

Solving it;

3x + 3y = 9

3x + 3 * (4.75 - 2x) = 9

3x + 14.25 - 6x = 9

-3x = 9 - 14.25

-3x = -5.25

x= -5.25/-3

x = 1.75

y = 4.75 - 2x

= 4.75 - 2 * 1.75

= 1.25

Hamburgers are x so they cost $1.75 each.

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You want to buy some rice. A 7-ounce package costs 2.59. A 12- ounce package costs $4.56. An 18-ounce package costs 6.30 which p
Reika [66]

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7-ounce package costs = 2.59.

Cost of 1-ounce of Type 1 rice= 2.59/7 = $0.37

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Cost of 1-ounce Type 2 rice = 4.56/12 = $0.38

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What property would you use first to solve 1/2x-6=10
NISA [10]

I don't know what you mean by property. Do you mean like, commutative, distributive, etc?

but, if this is what you mean:

to solve this:

The operation here is subtraction. Do the inverse. So, add 6 to both sides of the equation

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3 years ago
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