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Anvisha [2.4K]
4 years ago
5

2+2+2000+4000+5000+6000

Mathematics
2 answers:
sukhopar [10]4 years ago
8 0

Answer:

17004

Step-by-step explanation:

Over [174]4 years ago
3 0

Answer:

17004

Step-by-step explanation:

j add :0

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Mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
Paraphin [41]

Answer:

nnnnnnnnnnnnnnnnnnnnnnnnnn nnnnnnn

5 0
3 years ago
Can someone PLEASE help me solve these last 2 problems so I can be done with this math class....really stumped on these 2....
dexar [7]
Both distances 3966 and 4746 were done in 6 hours, so the speeds are:
speed against wind = 3966/6=661 km/h (difference of airplane and wind)
speed with wind = 4746/6=791 km/h (sum of airplane and wind)

The speed of airplane is greater than that of the wind, so this is a sum and difference problem.

Greater speed (plane) = (sum+difference)/2=(791+661)/2=726 km/h
Lesser speed (wind) = (sum-difference)/2 = (791-661)/2 = 65 km/h

3 0
3 years ago
David writes that the ratio of girls toboys is 1:4 orl. He tells his teacher that one-fourth of the students are girls. Is David
Aneli [31]

Answer:

i think it is no

Step-by-step explanation:

because 1+4=5

and girls are one so i think it is 1/5

hopefully i am right

7 0
4 years ago
When is the equation <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx-7%7D%7Bx%5E2-4x-21%7D%20%3D%5Cfrac%7B1%7D%7Bx%2B3%7D" id="Tex
Vladimir79 [104]

Notice that

x^2 - 4x - 21 = (x - 7) (x + 3)

so on the left side, a factor of <em>x</em> - 7 in the numerator and denominator can cancel

\dfrac{x-7}{x^2-4x-21} = \dfrac{x-7}{(x-7)(x+3)} = \dfrac1{x+3}

But we can only cancel them out as long as <em>x</em> ≠ 7 (because otherwise we'd have the indeterminate form 0/0 on the left side).

So, the equation is true for all <em>x</em> <u>except</u> <em>x</em> = 7. In set notation,

\{x \in \mathbb R \mid x \neq 7\}

In interval notation,

(-\infty,7)\cup(7,\infty)

8 0
3 years ago
4÷5 = 12 divided by how much
mihalych1998 [28]

Answer:

4/2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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