Answer:
a) The genes present on separate chromosomes exhibit indepedent assortment.
b) The genotype of tall and purple flower parent= TTPp
The genotype of short and purple flower parent: ttPp
Explanation:
a) In a dihybrid cross, if the genes are present on the same chromosome, they will not exhibit independent assortment. The genes present on the same chromosome are called linked genes. Linked genes are inherited together. The absence of independent assortment of a linked gene gives more of parental types in F2 progeny. Therefore, if genes are not present on a separate chromosome, Mendel’s ratios deviate.
b) Alleles for tallness and purple flower are dominant. In the progeny, all the plants are tall. This means that the dominant tall plant is homozygous. With respect to flower color, the trait exhibits segregation of dominant and recessive alleles and both purple and white flower progeny are obtained. This makes both the plants heterozygous for the flower color gene.
The genotype of tall and purple flower parent= TTPp
The genotype of short and purple flower parent: ttPp
3A)Amino acids-peptide
3B)Enzymes–speed up
3C)Active sites–substrate
3D)Unchanged
3E)[follow the instructions given]
4A)DNA—RNA
4B)Nucleotide—Deoxyribose–Phosphate–Nitrogen base
4C)DNA
4D)Thymine–Adenine—Cytosine–Guanine
4E)Hydrogen bonds
Answer:
The genotype represents two alleles.
Explanation:
The genotype represents two alleles. Because each pair of alleles represents the genotype of a specific gene.
<span>Meiosis consists of one round of DNA replication accompanied by two rounds of cell division.
Before meiosis starts, the cell </span><span>goes through an interphase period in which it grows, replicates its chromosomes to have enough material to divide for the daughter cells.
Unlike mitosis, meiosis has 2 cell division (meiosis
I and II). At the end of the first division, </span><span>each cell has half the number of chromosomes of the parent cell. At the end of the second division</span> there is separation of the sister chromatids
The answer is a C. The offsprings from this generation are from a cross between parents who are heterozygous (one parent) and homozygous recessive. This means that all the offsprings of the filial 1 (one) generation will carry a recessive allele. However, those with an equivalent dominant allele will not exhibit the attached earlobe trait. This is shown by the Punnet square below;
