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atroni [7]
3 years ago
6

Emeline can type at a constant rate of 1/4 pages/minute.

Mathematics
1 answer:
Degger [83]3 years ago
4 0

Answer:

a. 1/4

b. No, she does not have enough time

c. 28 minutes

Step-by-step explanation:

Emeline can type at a constant rate of 1/4 pages/minute.

a.the ratio of the number of pages to the number of minutes = 1/4 that she types 1 page every 4 minutes.

b. For a five page article she will take 5×4 minutes = 20 minutes( as she took 4 minutes for 1 page ). She won,t be able to complete task  before the dead line as she has got only 18 days.

c. Emeline has to type a 7-page article. so, she will take 7×4 minutes = 28 minutes to complete the task.

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Can anyone do this ??
Ilya [14]

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Step-by-step explanation:

7 0
4 years ago
Which point is collinear with points a and d
Art [367]
B. (6, -8)

First, you need to figure out the slope of the line

(y1 - y2) / (x1 - x2)

After substituting points D(-3, 4) A(3, -4)

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(8) / (-6)

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Then you can put it in point slope form:

(y - y1) = m(x - x1)

(y - y1) = -4/3(x - x1)

The point that I am using for point slope form is A(3, -4)

[y - (-4)] = -4/3(x - 3)
y + 4 = -4/3(x - 3)

Next you have to simplify the equation so that y is isolated

y + 4 = -4/3(x - 3)

First distribute the -4/3

y + 4 = -4/3(x) + (-4/3)(-3)
y + 4 = -4/3x + 4

Subtract 4 on both sides
y + 4 - 4 = -4/3x + 4 - 4
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Now that you have y = -4/3x, you can substitute the values until one of them makes the equation equal

For example) (6, -8)
-8 = -4/3(6)
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~~hope this helps~~

6 0
4 years ago
A 90 percent confidence interval is to be created to estimate the proportion of television viewers in a certain area who favor m
Dominik [7]

Answer:

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The width of the interval is:

W = 2z\sqrt{\frac{\pi(1-\pi)}{n}}

In this sample:

Two 90% intervals, with different lenghts. So both have the same values for z an \pi

Interval A:

9000 viewers.

So the width is

W_{A} = 2z\sqrt{\frac{\pi(1-\pi)}{9000}}

Interval B:

100 viewers

So the width is

W_{B} = 2z\sqrt{\frac{\pi(1-\pi)}{1000}}

Relationship between the widths:

R = \frac{W_{A}}{W_{B}} = \frac{2z\sqrt{\frac{\pi(1-\pi)}{9000}}}{2z\sqrt{\frac{\pi(1-\pi)}{1000}}} = \frac{\sqrt{1000}}{\sqrt{9000}} = \frac{\sqrt{1}}{\sqrt{9}} = \frac{1}{3}

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

8 0
3 years ago
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