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3 years ago

8

Please help!

1 answer:

Lubov Fominskaja [6]3 years ago

8 0

Answer:

The answer is d (-21/2 , 2)

Step-by-step explanation:

That's where the lines meet up

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Do u guys mind helping me??

Rasek [7]

Answer:

I think the constant is 2.

Step-by-step explanation:

5 is coefficient because it is with a variable. So 5 cannot be constant.

5 0

3 years ago

A social work researcher has decided to do a study of people who have adopted children from outside the United States. He asks a

garri49 [273]

Answer:

The correct option is 1

Step-by-step explanation:

Snowball sampling is a typr of sampling technique which is used in investigating hard to reach groups. Existing subjects are asked to nominate further suubjects known to them, thereby making the sample increase like a rolling snowball

6 0

4 years ago

Which expression is equivalent to 4x – 5 ?

Dafna11 [192]

Answer:

I think it's D.........

6 0

3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

3 years ago

Rewrite the function by completing the square. f(x)= x^{2} -9 x +14f(x)=x 2 −9x+14

Bess [88]

Answer:

$f(x)=(x-4.5)^{2}-6.25$ or $f(x)=(1/4)(2x-9)^{2}-6.25$

Step-by-step explanation:

we have

$f(x)=x^{2}-9x+14$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-14=x^{2}-9x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-14+4.5^{2}=x^{2}-9x+4.5^{2}$

$f(x)+6.25=x^{2}-9x+4.5^{2}$

Rewrite as perfect squares

$f(x)+6.25=(x-4.5)^{2}$

$f(x)=(x-4.5)^{2}-6.25$

$f(x)=(1/4)(2x-9)^{2}-6.25$

5 0

3 years ago