The midpoint of the segment with endpoints <span>(10, 6) and (-4, 8) would be
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(i) XYZ = 180 - 64
= 116 degrees
Opposite angles in a cyclic quadrilateral add up to 180 degrees
(ii) YXZ = 23 degrees
Alternate angles in a segment are the same
(iii) OXZ = 26
XOZ = 64 x 2
= 128 degrees
The the angle at the centre is double the angle at the circumference.
180 - 128 = 52
OXZ = 52/2
= 26
Triangle OZX is an isosceles triangle
(Don't forget to include the reasons above full marks)
2. -11 sq rt of 112
Sq rt of 16 times sq rt of 7
Becomes 4 sq rt of 7
Multiply -11 times 4 sq rt of 7
-44 sq rt of 7
Answer A
3. Subtract 17-9 since they are hitch the same sq rt
Answer 8 sq rt of 17
The answer is b 120 . you add the angles