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mariarad [96]
2 years ago
9

Solve on the interval [0,2%): 2 cos²x+3cosx+1=0

Mathematics
1 answer:
agasfer [191]2 years ago
5 0

Answer:

Step-by-step explanation:

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Identify the volume of the composite figure rounded to the nearest tenth. HELP PLEASE!!
nirvana33 [79]

Answer:

V = 115.3 ft³

Step-by-step explanation:

The left part of the figure shows a cube of side length 4.2 ft.  The volume of a cube is V = s³, where s is the side length.  Hence, the volume of this particular cube is V = (4.2 ft)³ = 74.088.

The volume of a pyramid is V = (1/3)(base area)(height).

Here V = (1/3)(4.2 ft)²(7 ft) = 41.16 ft³.

Summing up the two distinct areas, we get V = 41.16 ft³ + 74.088 ft³, or

V = 115.3 ft³ after rounding up to the nearest tenth.

3 0
3 years ago
Find the volume of the frog queen building in Graz, Austria. The building is 18 meters long, 17 meters tall, and 18 meters wide
densk [106]

Answer: 5,508 m3

Step-by-step explanation:  V= 18 x 17 x 18 = 5,508 m3

8 0
3 years ago
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A. f(x) = l-2xl - 3<br> Domain: {1, 2, 3}<br> Find the range
gizmo_the_mogwai [7]

Hello there!

We are given the function:

\displaystyle \large{ f(x) =  | - 2x|  - 3} \\

To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.

Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.

So, we substitute x = 1,2 and 3 in the function.

<u>x</u><u> </u><u>=</u><u> </u><u>1</u>

\displaystyle \large{ f(1) =  | - 2(1)|  - 3} \\   \displaystyle \large{ f(1) =  | - 2|  - 3} \\

Recall that any numbers in absolute value are always positive.

\displaystyle \large{ f(1) =  2 - 3} \\   \displaystyle \large{ f(1) =   - 1} \\

<u>x</u><u> </u><u>=</u><u> </u><u>2</u>

\displaystyle \large{ f(2) =  | - 2(2)|  - 3} \\   \displaystyle \large{ f(2) =  | - 4 |   - 3} \\   \displaystyle \large{ f(2) =  4 - 3} \\   \displaystyle \large{ f(2) =  1}

<u>x</u><u> </u><u>=</u><u> </u><u>3</u>

\displaystyle \large{ f(3) =  | - 2(3)|  - 3} \\   \displaystyle \large{ f(3) =  | - 6|   - 3} \\   \displaystyle \large{ f(3) =  6 - 3} \\   \displaystyle \large{ f(3) =  3}

Therefore, Range: {-1,1,3}

Let me know if you have any questions!

Topic: Absolute Value Function / Modulus Function

6 0
3 years ago
Use a table to write a funtion
Lady bird [3.3K]
I see no table sorry
8 0
3 years ago
What is the slope-intercept form of the equation -3x + y=12
Musya8 [376]
Answer: y=3x+12

explanation: just add the 3x to the 12
8 0
3 years ago
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