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dalvyx [7]
4 years ago
8

What is the phase shift and period for the function y = 5cos2(θ + 45°) − 7?

Mathematics
1 answer:
galben [10]4 years ago
8 0
5cos2(x + 45) - 7
The period for cos = 2pi/k
The k = 2 so the period = pi
The phase shift is 45 degrees to the left.
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Laura is graphing an absolute-value function in the form
Ilya [14]

Answer:

The equation of the function is;

y = |x-3| -3

Step-by-step explanation:

Here, we want to give the absolute-value function

For the minimum value to be -3, it means that k is negative

since the domain is the set of all real numbers, then we do not have any undefined value for the range y

So, the equation is ;

y = |x-3| - 3

7 0
3 years ago
Given: KLMN is a trapezoid m∠N = m∠KML ME ⊥ KN , ME = 3 5 , KE = 8, LM KN = 3 5 Find: KM, LM, KN, Area of KLMN
prisoha [69]
A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the 
KM² = KE² + ME²KM² = 8² + (3√5)²       = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N  Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the  formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM)          = 1/2 * 3√5 * (40 + 24)         = 1/2 * 3√5 * 64         = 3 x 2.23 * 32         = 214.66 units²
7 0
3 years ago
the slopes of a quadrilateral are -1/2, 3/2, -1/2, and 3/2. What conclusion about this shape cam be made.​
Talja [164]

The conclusion that can be made given the slopes of the quadrilateral is that: since the slopes of the opposite sides are equal, the opposite sides are parallel, therefore the quadrilateral is a parallelogram. (Option A is correct).

<em><u>Recall:</u></em>

  • The slopes of the opposite sides of a parallelogram are always parallel.
  • When two lines have a slope that is equal, the lines are said to be parallel to each other.

The slopes given shows are:

-1/2, 3/2, -1/2, and 3/2

This implies that the quadrilateral has two pairs of equal sides that are parallel to each other.

  • Therefore, the conclusion that can be made given the slopes of the quadrilateral is that: since the slopes of the opposite sides are equal, the opposite sides are parallel, therefore the quadrilateral is a parallelogram. (Option A is correct).

Learn more about parallelogram on:

brainly.com/question/3050890

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Solve 7log9(x + 8) = 7
Bumek [7]
Remember
log_a(b)=c translates to a^c=b

alrighty

so we've got
7log_9(x+8)=7
divide both sides by 7
log_9(x+8)=1
translate
9^1=x+8
9=x+8
minus 8 both sides
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x=1
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I just took a guest and say 20
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