Question

Solve 7log9(x + 8) = 7

Answer 1

Remember
$log_a(b)=c$ translates to $a^c=b$

alrighty

so we've got
$7log_9(x+8)=7$
divide both sides by 7
$log_9(x+8)=1$
translate
$9^1=x+8$
9=x+8
minus 8 both sides
1=x
x=1