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Marat540 [252]
3 years ago
6

Manuel bought a balloon (that is a perfect sphere) with a radius of 2 \text{ cm}2 cm2, space, c, m. He wanted his balloon to be

bigger, so he blew 222 big breaths of air into the balloon. Each big breath increased the balloon's radius by 1 \text{ cm}1 cm1, space, c, m. What is the ratio of the current volume of the balloon to the original volume of the balloon?
Mathematics
2 answers:
jonny [76]3 years ago
6 0
The original volume of the balloon is given by:
 V1 = (4/3) * (pi) * (r ^ 3)
 Where,
 r: radius of the sphere.
 Substituting values:
 V1 = (4/3) * (pi) * (1 ^ 3)
 V1 = (4/3) * (pi) * (1)
 Then, the volume of the current sphere is:
 V2 = (4/3) * (pi) * ((1 + 2 * (1)) ^ 3)
 V2 = (4/3) * (pi) * ((1 + 2) ^ 3)
 V2 = (4/3) * (pi) * ((3) ^ 3)
 V2 = (4/3) * (pi) * (27)
 The relation of volumes is:
 V2 / V1 = ((4/3) * (pi) * (27)) / ((4/3) * (pi) * (1))
 V2 / V1 = 27/1
 Answer:
 
The ratio of the current volume of the balloon to the original volume of the balloon is:
 
27: 1
nirvana33 [79]3 years ago
3 0

Answer:

8 times

Step-by-step explanation:

I found the volume of the sphere. Then increased it how many times he blew. That was the ratio.

Also, Khan :)

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