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KIM [24]
3 years ago
10

Which payment type is best if you are trying to stick to a budget?

Computers and Technology
2 answers:
GaryK [48]3 years ago
7 0
Probably a debit card because you can have a savings and only use the money you need to use without having cash and being tempted.
Westkost [7]3 years ago
7 0
I would go with debit card
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What happens it the offshore team members are not able to participate in the iteration demo due to time zone/infrastructure issu
professor190 [17]

The best option that will suite is that there will be no major issues since the offshore leads and the onsite members participated in the demo with the Product Owner/Stakeholders they can cascade the feedback to the offshore members

Explanation:

Iteration demo is the review which is done to gather the immediate feedback from the stakeholders on a regular basis from the regular cadence. This demo will be one mainly to review the progress of the team and the and to cascade and show their working process

They show their working process to the owners and they and the other stakeholders and they get their review from them and so there will be no issues if the members are not able to participate

5 0
4 years ago
Write a program that unpickle's employee dictionary and while reading from the dictionary, it allows users to lookup an employee
melamori03 [73]

Answer:

Check the explanation

Explanation:

from Employee import *

import pickle

import random

def unpickle_employee(filename):

file=open(filename,'rb')

data=pickle.load(file)

file.close()

return data

def pickle_employee(data,filename):

file=open(filename,'wb')

pickle.dump(data,file)

file.close()

if __name__=='__main__':

filename="Employees.dat"

'''

E=Employee("Ajay",1,"R&D","Manager")

data={}

data[1]=E

pickle_employee(data,filename)

'''

data=unpickle_employee(filename)

 

while True:

print("\nData In Employee.dat")

for d in data:

print("Employe data: ",data[d].get_name(),"({},{},{})".

format(data[d].get_id_number(),data[d].get_department(),data[d].get_job_title()))

 

print("\n\n\t\tMenu")

print("To add new Employee, Enter a")

print("To update any Employee, Enter u")

print("To delete any Employee, Enter d")

print("Enter anything to quit")

choice=input("Enter: ")

if choice=='a':

id_number=random.randrange(100,200,1)

while id_number in data:

id_number+=1

if id_number>=200:

id_number=100

name=input("Enter the Name: ")

department=input("Enter the Department: ")

job_title=input("Enter the job title: ")

E=Employee(name,id_number,department,job_title)

data[id_number]=E

elif choice=='u':

id_number=int(input("Enter the Employee id_number to update: "))

for d in data:

print(id_number,d,d==id_number)

if id_number in data:

print("Employe data: ",data[id_number].get_name(),"({},{})".

format(data[id_number].get_department(),data[id_number].get_job_title()))

print("\nPlease Enter the details")

name=input("Enter the Name: ")

department=input("Enter the Department: ")

job_title=input("Enter the job title: ")

E=Employee(name,id_number,department,job_title)

data[id_number]=E    

else:

print("Employee doesn't exist\n")

elif choice=='d':

id_number=int(input("Enter the Employee id_number to delete: "))

if id_number in data:

print("Employe data: ",data[id_number].get_name(),"({},{})".

format(data[id_number].get_department(),data[id_number].get_job_title()))

choice=input("\nPlease Enter y to confirm, anything else to cancel: ")

if choice=='y':

del data[id_number]

else:

print("Employee doesn't exist\n")

else:

break

pickle_employee(data,filename)

7 0
3 years ago
What is a focus of Accenture's point of view on blockchain in the marketplace?
Ipatiy [6.2K]

Answer:

enabling clients to store all their data, documents, and employee information on blockchain. accumulating the most data from wherever possible and building a comprehensive data lake.

Explanation:

4 0
3 years ago
Write a program for determining if a year is a leap year. In the Gregorian calendar system you can check if it is a leaper if it
SOVA2 [1]

Answer:

def leap_year_check(year):

return if int(year) % 4 == 0 and (int(year) % 100 != 0 or int(year) % 400 == 0)

Explanation:

The function is named leap_year_check and takes in an argument which is the year which we wish to determine if it's a new year or not.

int ensures the argument is read as an integer and not a float.

The % obtains the value of the remainder after a division exercise. A remainder of 0 means number is divisible by the quotient and a remainder other wise means it is not divisible by the quotient.

If the conditions is met, that is, (the first condition is true and either the second or Third condition is true)

the function leap_year_check returns a boolean ; true and false if otherwise.

8 0
3 years ago
What is Key benefit of using ram in a computer
deff fn [24]
There is not really a key benifit, but it does help with little things.
7 0
3 years ago
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