B. hand gestures
these are not verbal.
Answer:
while(userNum>=1){
System.out.print(userNum/2+" ");
userNum--;
}
Explanation:
This is implemented in Java programming language. Below is a complete code which prompts a user for the number, receives and stores this number in the variable userNum.
<em>import java.util.Scanner;</em>
<em>public class TestClock {</em>
<em> public static void main(String[] args) {</em>
<em> Scanner in = new Scanner (System.in);</em>
<em> System.out.println("Enter the number");</em>
<em> int userNum = in.nextInt();</em>
<em> while(userNum>=1){</em>
<em> System.out.print(userNum/2+" ");</em>
<em> userNum--;</em>
<em> }</em>
<em> }</em>
<em>}</em>
The condition for the while statement is userNum>=1 and after each iteration we subtract 1 from the value of userNum until reaching 1 (Hence userNum>=1)
Answer:
A light bulb produces light from electricity
Answer:
The correct Answer is 0.0571
Explanation:
53% of U.S. households have a PCs.
So, P(Having personal computer) = p = 0.53
Sample size(n) = 250
np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10
So, we can just estimate binomial distribution to normal distribution
Mean of proportion(p) = 0.53
Standard error of proportion(SE) = 
= 
= 0.0316
For x = 120, sample proportion(p) = 
= 
= 0.48
So, likelihood that fewer than 120 have a PC
= P(x < 120)
= P( p^ < 0.48 )
= P(z < 
) (z=
)
= P(z < -1.58)
= 0.0571 ( From normal table )
