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Nataly [62]
3 years ago
15

Ariel swims 2 1/6 miles in every 1/3 hour. Enter the number of miles Ariel swims in 1 minute.

Mathematics
1 answer:
weqwewe [10]3 years ago
4 0

In order to find the distance covered in 1 minute, we need to divide distance covered 2 1/6 miles by 20 minutes.We are given : Ariel swims 2 1/6 miles in every 1/3 hour.

Let us convert 1/3 hour into minutes.

There are 60 minutes in an hour.

Therefore, 1/3 hours = 60 × 1/3 = 20 minutes.

So, we could say, "Ariel swims 2 1/6 miles in every 20 minutes".


2 1/6÷ 20 = 13/6 ÷ 20.

Let us convert division sign into multiplication and flip 20 to 1/20.

We get

<h3>13/6 × 1/20 = 13/120 miles in 1 minute.</h3><h3>In decimal 0.11 mile in 1 minute.</h3>
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Nikitich [7]

Answer:

Area of nail's head  = 28.26 millimeter² (Approx.)

Step-by-step explanation:

Given:

Head of nail is circular

Diameter of nail's head = 6 millimeter

Find:

Area of nail's head

Computation:

Radius of nail's head = Diameter / 2

Radius of nail's head = 6 / 2

Radius of nail's head = 3 millimeter

Area of circle = πr²

Area of nail's head  = πr²

Area of nail's head  = (22/7)(3)²

Area of nail's head  = (22/7)(9)

Area of nail's head  = (3.14)(9)

Area of nail's head  = 28.26 millimeter² (Approx.)

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2 years ago
Given that r=(9,8,3),v=(6,7,-1)and w=(-3,3,7), evaluate (r+v) w
lakkis [162]

Answer:

(-45,45,14)

Step-by-step explanation:

(r+v)*w=((9,8,3)+(6,7,-1))*(-3,3,7)=(15,15,2)*(-3,3,7)=(-45,45,14)

Does this help (I'm not sure of the rightness of this answer), if it did, please mark brainliest

4 0
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Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
Tammy has scored 82, 78, and 93 on her previous three tests. What score does she need on her next test so that her average (mean
Lyrx [107]

Answer:

She needs a grade of 71 on her next text.

Step-by-step explanation:

Mean of a data-set:

The mean of a data-set is the sum of all values in the data-set divided by the number of values.

Tammy has scored 82, 78, and 93 on her previous three tests.

Thus, her grades are 82, 78, 93 and x, in which x is her grade in the fourth test.

There are 4 tests.

What score does she need on her next test so that her average (mean) is 81?

We have to find x when the mean is 81. So

\frac{82 + 78 + 93 + x}{4} = 81

253 + x = 324

x = 324 - 253

x = 71

She needs a grade of 71 on her next text.

5 0
3 years ago
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