Answer:
19/24
Step-by-step explanation:
From the question we are informed that Lisle bought 3/8 pounds of red grapes and 5/12 pound of green grapes
✓3/8 pounds of red grapes and 5//12
✓First thing to do is to add the fractions
But we need " the least common denominator" because their denominator are not the same, we need to make it the same...
✓ The two denominator ( 8 and 12) are both factor of 24, therefore their "least common denominator" is 24.
✓To make 3/8 pounds of red grapes has a denominator of 24, we multiply both the denominator & numerator with factor of 3.
3/8 = (3×3)/(8×3)=9/24
✓To make 5/12 pounds of green grapes has a denominator of 24, we multiply both the denominator & numerator with factor of 2.
5/12= (5×2)/(12×2)= 10/24
✓ we can see they both have the same denominator, then we can now "add both denominators"
(9+10)=19
✓ Then place the addition of the denominators on the least common denominator.
= 19/24.
Therefore, he bought 19/24 of grapes
STEP BY STEP
200+[-55]+[-77]+ [-68]
200+[-55-77-68]
200+[-200]
200 -200
0
PLEASE PLEASE MAKE ME THE BRAINLIST
23+24+25 Add these integers to equal 72.
Answer:
The statement is true is for any 
.
Step-by-step explanation:
First, we check the identity for 
:
The statement is true for .
Then, we have to check that identity is true for 
, under the assumption that 
is true:
![(1^{2}+2^{2}+3^{2}+...+k^{2}) + [2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}](https://tex.z-dn.net/?f=%281%5E%7B2%7D%2B2%5E%7B2%7D%2B3%5E%7B2%7D%2B...%2Bk%5E%7B2%7D%29%20%2B%20%5B2%5Ccdot%20%28k%2B1%29-1%5D%5E%7B2%7D%20%3D%20%5Cfrac%7B%28k%2B1%29%5Ccdot%20%5B2%5Ccdot%20%28k%2B1%29-1%5D%5Ccdot%20%5B2%5Ccdot%20%28k%2B1%29%2B1%5D%7D%7B3%7D)
![\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)}{3} +[2\cdot (k+1)-1]^{2} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}](https://tex.z-dn.net/?f=%5Cfrac%7Bk%5Ccdot%20%282%5Ccdot%20k%20-1%29%5Ccdot%20%282%5Ccdot%20k%20%2B1%29%7D%7B3%7D%20%2B%5B2%5Ccdot%20%28k%2B1%29-1%5D%5E%7B2%7D%20%3D%20%5Cfrac%7B%28k%2B1%29%5Ccdot%20%5B2%5Ccdot%20%28k%2B1%29-1%5D%5Ccdot%20%5B2%5Ccdot%20%28k%2B1%29%2B1%5D%7D%7B3%7D)
![\frac{k\cdot (2\cdot k -1)\cdot (2\cdot k +1)+3\cdot [2\cdot (k+1)-1]^{2}}{3} = \frac{(k+1)\cdot [2\cdot (k+1)-1]\cdot [2\cdot (k+1)+1]}{3}](https://tex.z-dn.net/?f=%5Cfrac%7Bk%5Ccdot%20%282%5Ccdot%20k%20-1%29%5Ccdot%20%282%5Ccdot%20k%20%2B1%29%2B3%5Ccdot%20%5B2%5Ccdot%20%28k%2B1%29-1%5D%5E%7B2%7D%7D%7B3%7D%20%3D%20%5Cfrac%7B%28k%2B1%29%5Ccdot%20%5B2%5Ccdot%20%28k%2B1%29-1%5D%5Ccdot%20%5B2%5Ccdot%20%28k%2B1%29%2B1%5D%7D%7B3%7D)
![(2\cdot k +1)\cdot [k\cdot (2\cdot k -1)+3\cdot (2\cdot k +1)] = (k+1) \cdot (2\cdot k +1)\cdot (2\cdot k +3)](https://tex.z-dn.net/?f=%282%5Ccdot%20k%20%2B1%29%5Ccdot%20%5Bk%5Ccdot%20%282%5Ccdot%20k%20-1%29%2B3%5Ccdot%20%282%5Ccdot%20k%20%2B1%29%5D%20%3D%20%28k%2B1%29%20%5Ccdot%20%282%5Ccdot%20k%20%2B1%29%5Ccdot%20%282%5Ccdot%20k%20%2B3%29)
Therefore, the statement is true for any .
Solution:
we are goiven that
The cost is $588 per person.
we have been asked to find
How much will it cost for the entire group of 8 students to attend?
As we are give with the cost for one person, so for 8 person , we will multiply the given cost by 8.
Cost for the entire group of 8 students to attend
$
Hence the Cost for the entire group of 8 students to attend is 4704 $
