Question

A helium-filled blimp stays aloft since helium is less dense than regular air, so helium will rise above regular

Answer 1

Answer:

The blimp can carry 70 passengers

Step-by-step explanation:

Lets use the ratio method to solve this problem

∵ 1 cubic meter of helium  can lift about 1.1 kg

∵ A blimp can carry as much as 2 x $10^{5}$ m³ of helium

By using the ratio method

→  m³         :  kg

→  1            :  1.1

→  2 x $10^{5}$   :  x

By using cross multiplication

∴ x × 1 = 1.1 × 2 x $10^{5}$

∴ x = 2.2 x $10^{5}$

∵ x represents the mass that can carried by the helium

∴  2 x $10^{5}$ m³ of helium can lift 2.2 x $10^{5}$ kg

∵ The mass of the blimp is 2.13 x $10^{5}$ kg

- Subtract the mass of the blimp from the mass that the given

    amount of helium can lift to find the mass of the passengers

∴ The mass of the passengers = 2.2 x $10^{5}$ - 2.13 x $10^{5}$

- Subtract 2.13 from 2.2 ⇒ 2.2 - 2.13 = 0.07

∴ The mass of the passengers = 0.07 x $10^{5}$

∵ The average mass of a person with luggage is 10² kg

- Divide the mass of the passengers by the mass of the person

   to find the number of the passengers

∴ The number of passengers = 0.07 x $10^{5}$ ÷ 10²

- Subtract the exponents of 10 to find the answer

∵ $10^{5}$ ÷ 10² = $10^{5-2}$ = 10³

∴ The number of passengers = 0.07 x 10³

∴ The number of passengers = 0.07 × 1000

∴ The number of passengers = 70

The blimp can carry 70 passengers