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3 years ago

If I buy one 6-pack of soda can fizzy candy for $1.25 Then how much will it be if I bought 25 6-packs of the candy.

Mathematics

2 answers:

enyata [817]3 years ago

4 0

The answer is 31.25 because 25*1.25 is 31.25

BabaBlast [244]3 years ago

3 0

25*1.25=31.25 is your answer. If that is not correct, I would be more than happy to do further research to aid you to find the answer.

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I dont know what to do please help me

ipn [44]

Answer:

Step-by-step explanation:

Time Distance

0 0

2 2*25 = 50

4 4*25 = 100

6 6*25= 150

8 8 * 25 = 200

7 0

2 years ago

Ally collects stickers as a hobby. She gives her sisters of her stickers.

sertanlavr [38]

Answer:

$\frac{16}{25}$

Step-by-step explanation:

Ally gives her sister = 1/5 stickers

Ally gives her cousin = 1/5 of the remainder stickers

Assume Number of sticker Ali has = 1

Remainder after giving stickers to her sister = 1 - 1/5 = 4/5

Number of stickers she gave her sister = $\frac{1}{5}\times\frac{4}{5}$

= $\frac{4}{25}$

Sticker she has = $1-\frac{1}{5}-\frac{4}{25}$

= $\frac{25-5-4}{25}$

= $\frac{16}{25}$

Sticker left with Ally is equal to $\frac{16}{25}$ .

7 0

2 years ago

Carlos says there are a total of 6,000 hundreds in the number 6,000,000.

Anna11 [10]

I would say B but I'm not sure

7 0

3 years ago

A certain book had an original rating of 27 out of 30 points on a survey chart. Each month, the rating fell by 3 points. Express

Natali [406]

Answer:

D.) f(m)=27−3m

Step-by-step explanation:

Given that:

Original rating = 27

Total possible rating points = 30

Drop in rating point per month = 3

m = number of months since release :

Hence,

F(m) = original rating - drop in rating per month * number of months since release

F(m) = 27 - 3(m)

F(m) = 27 - 3m

7 0

2 years ago

If tn = 4n+1, find t1, t2, t3, and tn+1. Express tn+1−tn in its simplest form.

Doss [256]

Answer:

$t_1=5$

$t_2=9$

$t_3=13$

$t_{n+1}-t_n=4$

Step-by-step explanation:

We have that:

$t_n=4n+1$

When we substitute n=1, we get:

$t_1=4*1+1=5$

When we substitute n=2 we get:

$t_2=4*2+1=9$

When we substitute n=3, we get:

$t_3=4*3+1=13$

When we substitute n=n+1, we get:

$t_{n+1}=4*(n+1)+1=4n+5$

Now

$t_{n+1}-t_n=4n+5-(4n+1)$

We expand and simplify to obtain:

$t_{n+1}-t_n=4n+5-4n-1$

$t_{n+1}-t_n=4$

3 0

3 years ago