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2 years ago

If I buy one 6-pack of soda can fizzy candy for $1.25 Then how much will it be if I bought 25 6-packs of the candy.

Mathematics

2 answers:

enyata [817]2 years ago

4 0

The answer is 31.25 because 25*1.25 is 31.25

BabaBlast [244]2 years ago

3 0

25*1.25=31.25 is your answer. If that is not correct, I would be more than happy to do further research to aid you to find the answer.

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2 Find the slope from the 2 points. (-12,-9) and ( 18, 6) -2 -1/2 2 1/2

lawyer [7]

Step-by-step explanation:

the slope of a line is the ratio y/x.

that means when going from one point to the other, how many units is y changing, when x changes a certain number of units.

so, going from one point to the other here, x changes by 30 units (from -12 to +18). and y changes 15 units (from -9 to 6).

therefore, the slope is

15/30 = 1/2

8 0

2 years ago

If nine times a certain number is subtracted from 7 the result is 52. Find the number.

mezya [45]

Answer:

Let the number to find be x

7 - 9x = 52

-9x = 52-7

- 9x = -45

Divide by - 9

x = 5

The number is 5

Hope this helps.

6 0

3 years ago

Read 2 more answers

(a) Predict the median income of a region in which 30% of adults 25 years and older have at least a bachelor's degree.

Step2247 [10]

Answer:

(a). $35746. (b). Higher.

Step-by-step explanation:

(a). Given that the least-squares regression equation is y = 7163x + 14242. Also, in the question above we are given that y is the median income and x is the percentage of 25 years and older with at least a bachelor's degree in the region, that is to say that the value of x = 30.

Therefore, y = 7163x + 14242.

y = (7163 × 30) + 14242.

y = $35746.

(b). The condition for our x is; 28.7 percent of adults 25 years and older have at least a bachelor's degree.

Then, y = (7163 × 28.7) + 14242.

y = $34814.

Hence, we have the median income in this region = $38,163 HIGHER than $34814.

4 0

2 years ago

A parking lot contains 100 cars , k of which happen to be lemons. we select m of these cars

Sunny_sXe [5.5K]

Given that a parking lot contains 100 cars, k of which happen to be lemons.

This is a conditional probability question.

Let event A be that a car is tested and event B be that a car is lemon.

The probability that a car is lemon is given by $\frac{k}{100}$

The probability that a car is tested is given by $\frac{m}{100}$

The probability that a car is lemon and it is tested is given by $\frac{n}{m}$

For a conditional probability, the probablility of event A given event B is given by:

$P(A|B)= \frac{P(A\cap B)}{P(B)}$

Therefore, the probability that a car is lemon, given that it is tested is given by.

$P(lemon|tested)= \frac{P(lemon\, and\, tested)}{P(tested)} \\ \\ = \frac{ \frac{n}{m} }{ \frac{m}{100} } = \frac{n}{m} \times \frac{100}{m} = \frac{100n}{m^2}$