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Nady [450]
2 years ago
13

What would you do if you found two values that were twice as big as the next highest value?

Mathematics
1 answer:
DedPeter [7]2 years ago
5 0

If I discovered two numerical values that were twice as big as the next highest value, I would expunge them because they can affect the final results.

<h3>What is a numerical data?</h3>

A numerical data is also referred to as a quantitative data and it can be defined as a data set that is primarily expressed in numbers only.

This ultimately implies that, a numerical data is a data set consisting of numbers rather than words.

<h3>What is an outlier?</h3>

An outlier can be defined as a numerical value that is either unusually too small or large (big) in comparison with the overall pattern of the numerical values contained in a data set.

Assuming I am counting the number of expert tutors on Brainly and I discovered two numerical values that were twice as big as the next highest value, I would expunge them because they can affect the final results.

Read more on outlier here: brainly.com/question/10600607

#SPJ1

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Is the amount of rain in city upper b during april a discrete random​ variable, a continuous random​ variable, or not a random​
larisa [96]
Answer: It is a continuous random variable.

The amount of rain is a continuous random variable because it can take on all of the numbers on a number line.

For example, the actual amount of rain in April could be 1 inch. Or 1.4 inches. Or 1.45 inches. Or 1.452020980234 inches. There are an infinite possibilities for the amount of rainfall.
6 0
3 years ago
I need help solving this equation
solmaris [256]

Answer:

-765

Step-by-step explanation:

-2-7 * 109

-2 - 763

-765

4 0
3 years ago
Read 2 more answers
1) What is the GCF for the polynomial 4x3 - 2x2y?
Dafna1 [17]

(1)the GCF for the polynomial 4x^3 - 2x^2y

4x^3 = 2*2* x* x* x

2x^2y = 2*x*x*y

Greatest common factor  is 2*x*x = 2x^2

(2) the GCF for the polynomial 8x^4y + 6x^2y^2

8x^4y = 2*2*2*x*x*x*x*y

6x^2y^2 = 3*2*x*x*y*y

GCF is  2*x*x*y=2x^2y

(3) the GCF for the polynomial12x^3y^2 - 20x^5y^3

12x^3y^2 = 2*2*3*x*x*x*y*y

20x^5y^3=5*2*2*x*x*x*x*x*y*y*y

GCF is 2*2*x*x*x*y*y= 4x^3y^2

(4) the GCF for the polynomial -10x^3y^4 - 16x^5y^2

-10x^3y^4 =-2*5*x*x*x*y*y*y*y

-16x^5y^2=-2*2*2*2*x*x*x*x*x*y*y

GCF is -2*x*x*x*y*y= -2x^3y^2



3 0
3 years ago
Read 2 more answers
Help please and thanks
kotykmax [81]
Last one is correct
5 0
4 years ago
f the price charged for a candy bar is​ p(x) cents, where p (x )equals 162 minus StartFraction x Over 10 EndFraction ​, then x t
andreev551 [17]

Answer:

a. 1620-x^2

b. x=810

c. Maximum value revenue=$656,100

Step-by-step explanation:

(a) Total revenue from sale of x thousand candy bars

P(x)=162 - x/10

Price of a candy bar=p(x)/100 in dollars

1000 candy bars will be sold for

=1000×p(x)/100

=10*p(x)

x thousand candy bars will be

Revenue=price × quantity

=10p(x)*x

=10(162-x/10) * x

=10( 1620-x/10) * x

=1620-x * x

=1620x-x^2

R(x)=1620x-x^2

(b) Value of x that leads to maximum revenue

R(x)=1620x-x^2

R'(x)=1620-2x

If R'(x)=0

Then,

1620-2x=0

1620=2x

Divide both sides by 2

810=x

x=810

(C) find the maximum revenue

R(x)=1620x-x^2

R(810)=1620x-x^2

=1620(810)-810^2

=1,312,200-656,100

=$656,100

7 0
4 years ago
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