The answer should be 7/10!
Answer:
900
Step-by-step explanation:
Let x gallons be the amount of pure antifreeze that should be added to the 30% solution to produce a solution that is 65% antifreeze. Then the total amount of antifreeze solution will be x+3 gallons.
There are 30% of pure antifreeze in 3 gallons of solution, then
3 gallons - 100%,
a gallons - 30%,
where a gallons is the amount of pure antifreeze in given solution.
Mathematically,

Now in new solution there will be x+0.9 gallons of pure antefreeze.
x+3 gallons - 100%,
x+0.9 - 65%
or

Answer: he should add 3 gallons of pure antifreeze.
Answer:
C. cot theta
Step-by-step explanation:
(csc theta -cot theta )/(sec theta -1)
csc = 1/ sin
cot = cos / sin
sec = 1 / cos
Let x = theta
(1/ sin x -cos x / sin x )/(1/ cos x -1)
Getting a common denominator in the denominator and combining terms
(1- cos x)/ sinx / ( 1 - cos x) / cos x
(1- cosx) (1- cosx)
----------- ÷ ------------
sinx cos x
Copy dot flip
(1- cosx) cosx
----------- * ------------
sinx 1 -cos x
Cancel like terms
cos x / sin x
cos / sin = cot
cot x
cot theta
<h3>Given:</h3>
- P= $50,000
- R= 10%
- T= 5 years
<h3>Note that:</h3>
- P= Principal amount
- R= Rate of interest
- T= Time period
<h3>Solution:</h3>

Let's substitute according to the formula.

<em>A=</em><em> </em><em>$80525.5</em>
Now, we can find the interest paid

We'll have to deduct the total amount from the principal amount.
Let's substitute according to the formula.

<em>I=</em><em> </em><em>$30525.5</em>
<u>Hence</u><u>,</u><u> </u><u>the</u><u> </u><u>total</u><u> </u><u>amount</u><u> </u><u>paid</u><u> </u><u>after</u><u> </u><u>5</u><u> </u><u>years</u><u> </u><u>is</u><u> </u><u>$</u><u>80525.5</u><u> </u><u>and</u><u> </u><u>$</u><u>30525.5</u><u> </u><u>was</u><u> </u><u>paid</u><u> </u><u>as</u><u> </u><u>interest</u><u>.</u>