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Answer:
db / dt = kb
this becomes b(t) = Ce^(kt)
C = 100, the initial population
P(1) = 420 = 100 e^(1k)
4.2 = e^k
ln 4.2 = k
a) thus, b(t) = 100 e^(t ln 4.2)
b) b(3) = 100 e^(3 ln 4.2)
c) growth constant will still be ln 4.2 (constant percentage of populatioin)
d) 10000 = 100 e^(t ln 4.2)
100 = e^(t ln 4.2)
ln 100 = t ln 4.2
t = ln 100 / ln 4.2
Step-by-step explanation:
Set up a system of equations:
2x+3y=6
x-3y=9
You can solve this with elimination by adding the two equations together:
3x+0y = 15
3x=15
x=5
Then, plug this value back into either of the original equations to find the y value:
5-3y=9
-3y=4
y= -4/3
The point of intersection is (5,-4/3)
Total cost as the function of shirts is :
C(x) = mx + 500 .
It is given that , The total cost to produce 100 shirts is $800.
800 = 100m + 500
m = 3
So , cost is given by :
C(x) = 3x + 500 .
Now , putting x = 1000 .
We get :
C(x) = 3x + 500
C(x) = 3(1000) + 500
C(x) = $3500
Therefore , cost of producing 1000 shirts is $3500 .
Hence, this is the required solution .
