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3 years ago

What are the most bags Mrs. Dupree can make? Will choose brainliest and will report absurd answers

Mathematics

1 answer:

Umnica [9.8K]3 years ago

3 0

Answer:

B. 4 bags

Step-by-step explanation:

The number of bags that will have the same quantities of the different gifts is the Greatest Common Divisor of the numbers of gifts.

GCD(24, 32, 44) = 4

Mrs. Dupree can make at most 4 identical bags.

___

The GCD can be found by looking at factors:

24 = 4·6
32 = 4·8
44 = 4·11

4 is the largest common factor of these numbers.

The GCD can also be found using Euclid's algorithm. In that algorithm, the larger number is divided by the smaller, with the remainder replacing the larger number after each step. If the remainder is zero, the smaller number is the GCD.

The GCD of several numbers can be found by finding the GCD of a pair, then of that value and the next number:

GCD(24, 32, 44) = GCD(GCD(24, 32), 44) = GCD(8, 44) = 4

32/24 = 1 r 8 . . . . first step in Euclid's algorithm for GCD(24, 32)

24/8 = 3 r 0 ⇒ GCD(24, 32) = 8

Then

44/8 = 5 r 4

8/4 = 2 r 0 ⇒ GCD(8, 44) = 4 = GCD(24, 32, 44)

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The figure below shows part of a stained-glass window depicting the rising sun. Which function can be used to find the area of t

Kryger [21]

Answer:

$A(w) = w^2 + 5w - \frac{1}{8}\pi w^2$

Step-by-step explanation:

A = the area of the region outside the semicircle but inside the rectangle

w = the width of the rectangle or diameter of the semicircle

Since "A" is determined by "w", therefore, "A" is a function of "w" = A(w).

A(w) = (area of rectangle) - (area of semicircle)

$A(w) = (l*w) - (\frac{1}{2} \pi r^2)$

Where,

lenght of rectangle (l) = w + 5

width of rectangle (w) = w

r = ½*w = $\frac{w}{2}$

Plug in the values:

$A(w) = ((w + 5)*w) - (\frac{1}{2} \pi (\frac{w}{2})^2)$

Simplify

$A(w) = (w^2 + 5w) - (\frac{1}{2} \pi (\frac{w^2}{4})$

$A(w) = w^2 + 5w - \frac{1}{2}*\pi*\frac{w^2}{4}* \pi$

$A(w) = w^2 + 5w - \frac{1*\pi*w^2}{2*4}$

$A(w) = w^2 + 5w - \frac{1*\pi w^2}{8}$

$A(w) = w^2 + 5w - \frac{1}{8}\pi w^2$

3 0

3 years ago

How are rates and ratios related

Dovator [93]

Rates are the percentage and ratios are like this 3:1. so, in that 3:1 ratio, there is 3 to 1 cookies to cups of milk. So there is 75% cookies and 25% milk.

I hope i helped you, comment and ill answer

7 0

4 years ago

Read 2 more answers

Question 1 (1 point)

s2008m [1.1K]

Answer:

d. -18

Step-by-step explanation:

f(-3) = 10x - 3x + 3

10(-3) - 3(-3) + 3

-30 + 9 + 3

-30 + 12

= -18

Please mark me the Brainliest!?!

8 0

3 years ago

Pwease help fast this is mah last question!

inessss [21]

Answer:

A = 222 units^2

Step-by-step explanation:

To find the area of this trapezoid, first draw an imaginary horizontal line parallel to AD and connecting C with AB (Call this point E). Below this line we have the triangle CEB with hypotenuse 13 units and vertical side (21 - 16) units, or 5 units. Then the width of the entire figure shown can be obtainied using the Pythagorean Theorem:

(5 units)^2 + CE^2 = (13 units)^2, or 25 + CE^2 = 169. Solving this for CE, we get |CE| = 12.

The area of this trapezoid is

A = (average vertical length)(width), which here is:

(21 + 16) units

A = --------------------- * (12 units), which simplifies to:

A = (37/2 units)(12 units) = A = 37*6 units = A = 222 units^2

8 0

4 years ago

In timara math class there are, 12 boys and 15 girls which of the following in the ratio to boys and girls in timaras math class

tiny-mole [99]

Answer:

4:5

Step-by-step explanation:

If there are 12 boys and 15 girls, the ratio of boys to girls will be 12:15.

However, this can be simplified by dividing each number by 3. This can be done since both 12 and 15 are divisible by 3.

12:15

= 4:5

So, the ratio of boys to girls in Timara's class is 4:5

7 0

3 years ago