Answer:
8.20in³
Step-by-step explanation:
Given V = πr²h
r is the radius = 1.5in
h is the height = 6in
thickness of wall of the cylinder dr = 0.04in
top and bottom thickness dh 0.07in+0.07in = 0.14in
To compute the volume, we will find the value of dV
dV = dV/dr • dr + dV/dh • dh
dV/dr = 2πrh
dV/dh = πr²
dV = 2πrh dr + πr² dh
Substituting the values into the formula
dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14
dV = 2π (0.36)+π(1.89)
dV = 0.72π+1.89π
dV = 2.61π
dV = 2.61(3.14)
dV = 8.1954in³
Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)
Answer:
Step-by-step explanation:
we know that
The volume of a right circular cone is equal to
where
r is the radius of the base of the cone
h is the height
Solve for r-----> That means, isolate the variable r
so
step 1
Multiply by 3 both sides
step 2
Divide by 
both sides
step 3
take square root boot sides
You have to make a proportion:
12+x/8=8/x
Then cross multiply to solve for x
Answer:3/6
Step-by-step explanation:
