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3 years ago

What is most reasonably measured in miles?

Mathematics

1 answer:

iris [78.8K]3 years ago

8 0

Answer:

Length of a Road

Step-by-step explanation: No man that has ever lived (Well unless they're a nephilim or smth) is over a mile tall. Swimming pools and buildings aren't usually big enough to be measured in miles unless they're either a skyscraper or a Wisconsin water park attraction.

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Kendra bought 235 donuts for $120. Her profit was $35 once she had sold 100 donuts. Which equation below represents Kendra’s pro

marysya [2.9K]

The last one
P(n) = 1.55n-120

5 0

3 years ago

Choose the correct simplification of the expression a^12b^8/a^2 b^4.

inysia [295]

$\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
\cfrac{a^{12}b^8}{a^2b^4}\implies a^{12}a^{-2}b^8b^{-4}\implies a^{12-2}b^{8-4}\implies a^{10}b^4$

6 0

3 years ago

I need to solve this

guajiro [1.7K]

Answer:

x is 7, y is -1

Step-by-step explanation:

x+7y=0

2x-8y=22 -> divide both sides by -2

x+7y=0

-x+4y=-11

Eliminate one of the equations by adding the equations.

11y=-11

y=-1

Substitue the value of y into te equation

x+7*(-1)=0

x=7

3 0

4 years ago

Life tests on a helicopter rotor bearing give a population mean value of 2500 hours and a population standard deviation of 135 h

stira [4]

Answer:

The percent of the parts are expected to fail before the 2100 hours is 0.15.

Step-by-step explanation:

Given :Life tests on a helicopter rotor bearing give a population mean value of 2500 hours and a population standard deviation of 135 hours.

To Find : If the specification requires that the bearing lasts at least 2100 hours, what percent of the parts are expected to fail before the 2100 hours?.

Solution:

We will use z score formula

$z=\frac{x-\mu}{\sigma}$

Mean value = $\mu = 2500$

Standard deviation = $\sigma = 135$

We are supposed to find If the specification requires that the bearing lasts at least 2100 hours, what percent of the parts are expected to fail before the 2100 hours?

So we are supposed to find P(z<2100)

so, x = 2100

Substitute the values in the formula

$z=\frac{2100-2500}{135}$

$z=−2.96$

Now to find P(z<2100) we will use z table

At z = −2.96 the value is 0.0015

So, In percent = $.0015 \times 100=0.15\%$

Hence The percent of the parts are expected to fail before the 2100 hours is 0.15.

5 0

3 years ago

Review the following problem and answer the questions that follow.

elena55 [62]

Answer:

1) 2 should be added with 12 only and not with 6x as 6x and 2 are not like terms.

2) When adding polynomials, You should add only like terms.

Step-by-step explanation:

The steps done are:

Step 1: y-2=6x+12

Step 2: Add 2 on both sides

y-2+2=6x+12+2

Answer : y=8x+14

1) What mistake did I made?

You made a mistake in step 2,

When adding polynomials, you add only like terms. i.e

y-2+2=6x+12+2

y=6x+14

2 should be added with 12 only and not with 6x as 6x and 2 are not like terms.

2) Suggestion to avoid Such mistake in the future.

When adding polynomials, You should add only like terms.

Like terms are those that have same degree of variables i,e

2x and 3x, 2x^2 and 3x^2, 2 and 3 they all are like terms.

You can add 2x and 3x but can't add 2x and 2x^2 as they are not like terms.

So, while solving polynomials always add like terms.

5 0

3 years ago