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3 years ago

Factor completely 21x3y4 + 15x2y2 − 12xy3.

1 answer:

8 0

Common factors are x, y^2, and 3, so

3xy^2(7x^2y^2+5x-4y^2)

You can see there's nothing left common to each term inside the parenthesis

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Joe is building a container to hold sand for a beach party. The container will hold 9,000 cubic feet of sand. Of the base of the

Genrish500 [490]

Answer:

The height of the container is 4 feet.

Step-by-step explanation:

A container has the format of a rectangular prism.

It has three dimensions: width(w), length(l), height(h).

The volume is:

$V = w*l*h$

In this question:

$w = 45, l = 50, V = 9000$

We have to find the height(length and width are in feet, volume in cubic feet, so the height will be in feet).

$V = w*l*h$

$9000 = 45*50*h$

$h = \frac{9000}{45*50}$

$h = 4$

The height of the container is 4 feet.

7 0

3 years ago

What are the real zeros of f(x) = x^3 +2x^2-5x-6

netineya [11]

First of all Horner
First we try with -3
1. 2. -5. -6.
-3. 3. 6
1. -1. -2. 0
To verify: -3^3+2*-3^2+15-6=0

Now we have this equation
(X+3)*(x^2 - x -2)=0

I dont know If you know sum and product but that is the easiest way so sum= 1 product = 2 so 2 and -1 are the answers.
You can do this too by this way : b^2-4ac= D
X= (-b(+or-)d^1/2)/2a

So all the zeros
2, -1 and -3
If you want more explanation, send me a comment x

8 0

4 years ago

What does a triangle with the measures 20,60, and 100 degrees look like?

irinina [24]

This most of the angles you asked about except for 20 i m not sure about it sorry

6 0

4 years ago

La familia brigg alquiló un carro por 5 semanas. <br> Cuanto costo alquilar el carro por semana

castortr0y [4]

<span>¿Cuál es el monto total que pagaron?</span>

4 0

3 years ago

If all the possible random samples with n = 36 scores are selected from a normal population with µ = 50 and σ = 18, and the mean

ozzi

Answer:

Expected Value of M is 50 and the Standard Error of M is 3

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation, also called standard error $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

µ = 50 and σ = 18

For the sample

Mean 50 and standard error $s = \frac{18}{\sqrt{36}} = 3$ .

The answer is:

Expected Value of M is 50 and the Standard Error of M is 3

7 0

3 years ago