1*1*1=1
D. 1 Cubic Unit(s)
height*width*length=volume
The question is kind of all over the place. Can you clear it up a bit because it sound to me that all you have to do is simple addition and subtraction hun.
Answer:
Probability that the lifetime of the machine part is less than 13 = 0.6782
Step-by-step explanation:
given that 
Normalizing the function we get





Answer:
x=100
Step-by-step explanation:
log10 x=2
10^2=x
100=x