Chi would have two thousand nickels because if 100 nickels is 5% and 100 divided 5 is 20 so a 100 times 20 is 2000
Answer:
It's the last choice: 2x^2 - 5x - 8 - 37/(x - 5).
Step-by-step explanation:
Long division:
2x^2 - 5x -8 <---------------Quotient
---------------------------------
x - 5 ) 2x^3 - 15x^2 + 17x + 3
2x^3 - 10x^2
- 5x^2 + 17x
- 5x^2 + 25x
- 8x + 3
- 8x + 40
-37 <------ Remainder.
<span>More please help me solve the problem
The stars have different brightness. The brightest stars are Grade 1 and the least degree luimnoase stars 6. The brightness of the stars shrinks 2.5 times with the passing from one grade to another. Whenever the stars are brighter Grade 1, Grade 6 than the stars?</span>
572 im pretty sure thats it
You can use Pythagoras theorem to find the radius.
r^2 + 8^2 = 10^2
r^2 + 64 = 100
r^2 = 36
r = 6
