What’s the correct answer for this?

Mathematics

1 answer:

ololo11 [35]2 years ago

4 0

As you can see in the picture, this is 6-8-10 right triangle.

One of angles is 90° so you can find others

$\tan( \alpha ) = \frac{opp}{adj}$

8/6 = 4/3

6/8= 3/4

tan-1(4/3) = 36.9 °

tan-1(3/4) = 53.1 °

tan<R= 53.1 °

Hope this helps ^-^

You might be interested in

Lol what.. its kinda bad tho

tino4ka555 [31]

What is bad ??!????????????!

6 0

3 years ago

Read 2 more answers

Anyone know the answer

Arlecino [84]

Answer: A: 2

Step-by-step explanation:

In order to find the slope of the line, you must know about rise/run, which means that you go up and over to your next point. For example: I started at the point 0,-4 and went up two and to the right one to the point -2,1, which i rose 2 and ran 1, or 2/1, which equals 2

3 0

2 years ago

How to solve this?<br>\int \frac { 4 - 3 x ^ { 2 } } { ( 3 x ^ { 2 } + 4 ) ^ { 2 } } d x

ivanzaharov [21]

$\Large \mathbb{SOLUTION:}$

$\begin{array}{l} \displaystyle \int \dfrac{4 - 3x^2}{(3x^2 + 4)^2} dx \\ \\ = \displaystyle \int \dfrac{4 - 3x^2}{x^2\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ = \displaystyle \int \dfrac{\dfrac{4}{x^2} - 3}{\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ \text{Let }u = 3x + \dfrac{4}{x} \implies du = \left(3 - \dfrac{4}{x^2}\right)\ dx \\ \\ \text{So the integral becomes} \\ \\ = \displaystyle -\int \dfrac{du}{u^2} \\ \\ = -\dfrac{u^{-2 + 1}}{-2 + 1} + C \\ \\ = \dfrac{1}{u} + C \\ \\ = \dfrac{1}{3x + \dfrac{4}{x}} + C \\ \\ = \boxed{\dfrac{x}{3x^2 + 4} + C}\end{array}$